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Statistical Analysis of the Document - Assignment Example

Summary
"Statistical Analysis of the Document" paper states that the statistical methods used are: Frequencies, Crosstabs since the dependent and independent variables are categorical variables, it is better to use the chi-square test rather than the other statistical procedures/test…
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Statistical Analysis of the Document
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Extract of sample "Statistical Analysis of the Document"

Statistical Analysis The statistical methods used is: Frequencies, Crosstabs since the dependent and independent variables are categorical variables, it is better to use chi square test rather than the other statistical procedures/test. 2. Simulation of data set for the variables which will be used for measurements. (Variables are identified in attached documents). The SPSS file containing these data is attached herewith. File name is ssri.sav. The variables under study are described as below: Variables 1: Depression: 1 Mild (14-19), 2 Moderate (20-28) 2: Drugs: 1 SSRI, 2 Natural alternatives 3. Alternative regimen: 1 routine colon hydrotherapy sessions; 2 vegetarian dietary lifestyle adjustment; 3 herbal combination 4. Interval: 0 the beginning of the study, 1 at 30 days, 2 at 60 days, and 3 at 90 days. 5. Region: 1 Rural 2 Urban 6 Side effects: 1 Moderate 2 Severe 3. The statistical software which will perform the statistical procedures required for the statistical methods is SPSS which is versatile for this kind of statistical analyses. 4. The statistical analysis on the simulation data set that would address the relationships underlying the research questions listed in the attached document. & 5. Interpretation of the output from these simulated analysis. FREQUENCIES VARIABLES=depres drug alternat interval sideeff cure /ORDER=ANALYSIS. Frequency tables 1. Depression level Depression level Frequency Percent 1 Mild 30 50 2 Moderate 30 50 Total 60 100 2. Drugs administered Drugs administered Frequency Percent 1 SSRI 31 51.7 2 Natural Alternatives 29 48.3 Total 60 100 3. Alternative regimen Alternative regimen Frequency Percent 1 Routine 29 48.3 2 Vegetrarian 16 26.7 3 Herbal combination 15 25 Total 60 100 4. Interval time period Interval time period Frequency Percent 1 At the beginning 16 26.7 2 at 30 days 15 25 3 at 60 days 13 21.7 4 at 90 days 16 26.7 Total 60 100 5. Side effects Side Effects Frequency Percent 1 Low 31 51.7 2 High 29 48.3 Total 60 100 6. Cured Cured Frequency Percent 0 No 30 50 1 Yes 30 50 Total 60 100 CROSSTABS /TABLES=depres drug alternat interval sideeff BY cure /FORMAT= AVALUE TABLES /STATISTIC=CHISQ /CELLS= COUNT. Analysis and Interpretation: 1. Null Hypothesis: There is no association between depression level and the effect (cure) at 5% level of significance. Alternative Hypothesis: There is an association between depression level and the effect (cure) at 5% level of significance. Depression level * Cured Crosstab Count Cured Total 0 No 1 Yes Depression level 1 Mild 16 14 30 2 Moderate 14 16 30 Total 30 30 60 Chi-Square Tests Value df Asymp. Sig. (2-sided) Exact Sig. (2-sided) Exact Sig. (1-sided) Pearson Chi-Square .267(b) 1 0.606 Continuity Correction(a) 0.067 1 0.796 Likelihood Ratio 0.267 1 0.605 Fishers Exact Test 0.797 0.398 Linear-by-Linear Association 0.262 1 0.609 N of Valid Cases 60 Interpretation: Since the Chi square value is 0.267 with probability 0.606 (>0.05) we accept our null hypothesis and say that there is no association between depression level and the effect (cure) at 5% level of significance. ie. regardless of the depression level the cure is at the same level. 2. Null Hypothesis: There is no association between drugs administered and the effect (cure) at 5% level of significance. Alternative Hypothesis: There is an association between drugs administered and the effect (cure) at 5% level of significance. Drugs administered * Cured Crosstab Count Cured Total 0 No 1 Yes Drugs administered 1 SSRI 15 16 31 2 Natural Alternatives 15 14 29 Total 30 30 60 Chi-Square Tests Value df Asymp. Sig. (2-sided) Exact Sig. (2-sided) Exact Sig. (1-sided) Pearson Chi-Square .067(b) 1 0.796 Continuity Correction(a) 0 1 1 Likelihood Ratio 0.067 1 0.796 Fishers Exact Test 1 0.5 Linear-by-Linear Association 0.066 1 0.798 N of Valid Cases 60 Interpretation: Since the Chi square value is 0.067 with probability 0.796 (>0.05) we accept our null hypothesis and say that there is no association between drugs administered and the effect (cure) at 5% level of significance. ie. regardless of the drugs administered the cure is at the same level. 3. Null Hypothesis: There is no association between alternative regimen and the effect (cure) at 5% level of significance. Alternative Hypothesis: There is an association between alternative regimen and the effect (cure) at 5% level of significance. Alternative regimen * Cured Count Cured Total 0 No 1 Yes Alternative regimen 1 Routine 15 14 29 2 Vegetrarian 8 8 16 3 Herbal combination 7 8 15 Total 30 30 60 Chi-Square Tests Value df Asymp. Sig. (2-sided) Pearson Chi-Square .101(a) 2 0.951 Likelihood Ratio 0.101 2 0.951 Linear-by-Linear Association 0.097 1 0.756 N of Valid Cases 60 Interpretation: Since the Chi square value is 0.101 with probability 0.951 (>0.05) we accept our null hypothesis and say that there is no association between alternative regimen and the effect (cure) at 5% level of significance. ie. regardless of the alternative regimen the cure is at the same level. 4. Null Hypothesis: There is no association between interval time period and the effect (cure) at 5% level of significance. Alternative Hypothesis: There is an association between interval time period and the effect (cure) at 5% level of significance. Interval time period * Cured Crosstab Count Cured Total 0 No 1 Yes Interval time period 1 At the beginning 8 8 16 2 at 30 days 7 8 15 3 at 60 days 7 6 13 4 at 90 days 8 8 16 Total 30 30 60 Chi-Square Tests Value df Asymp. Sig. (2-sided) Pearson Chi-Square .144(a) 3 0.986 Likelihood Ratio 0.144 3 0.986 Linear-by-Linear Association 0.012 1 0.911 N of Valid Cases 60 Interpretation: Since the Chi square value is 0.144 with probability 0.986 (>0.05) we accept our null hypothesis and say that there is no association between interval time period and the effect (cure) at 5% level of significance. I.e. regardless of the interval time period the cure is at the same level. 5. Null Hypothesis: There is no association between the side effects and the effect (cure) at 5% level of significance. Alternative Hypothesis: There is an association between the side effects and the effect (cure) at 5% level of significance. Side Effects * Cured Crosstab Count Cured Total 0 No 1 Yes Side Effects 1 Low 15 16 31 2 High 15 14 29 Total 30 30 60 Chi-Square Tests Value df Asymp. Sig. (2-sided) Exact Sig. (2-sided) Exact Sig. (1-sided) Pearson Chi-Square .067(b) 1 0.796 Continuity Correction(a) 0 1 1 Likelihood Ratio 0.067 1 0.796 Fishers Exact Test 1 0.5 Linear-by-Linear Association 0.066 1 0.798 N of Valid Cases 60 Interpretation: Since the Chi square value is 0.144 with probability 0.986 (>0.05) we accept our null hypothesis and say that there is no association between the side effects and the effect (cure) at 5% level of significance. ie. regardless of the side effects the cure is at the same level. Read More

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