Projectile : Velocity with Which a Projectile Is Launched - Lab Report Example

The ball was then pushed into the back making sure it did not move forward. A test shot was then made to determine where the ball lands after which a carbon paper was placed on the white sheet. The ball was then fired 6 different times and the distance traveled by the ball from where the ball left the launcher was recorded. Part B The position of the launcher was made in such a way that the launcher launches the ball at 200 the steps in part A were then repeated and data were recorded in Table 2 Results and Calculations Part A Table 1 Distance traveled by ball (m) 3.13 3.24 3.28 3.35 3.35 3.40 Height of launcher = ________ Average Distance traveled by ball = ___3.

29______ Part B Table 2 Distance traveled by ball (m) 4.69 4.58 4.70 4.74 4.76 4.79 Average Distance traveled by ball = __4.71_ Discussion and Answer to the questions (1) Using your data in part A, calculate how fast the ball comes out of the launcher. SHOW YOUR WORK. The initial Velocity, Therefore, = 0.82 seconds Since the motion was in a horizontal direction, the velocity of the ball was =8.03 m/s (2) The velocity of the ball out of the launcher is the same regardless of the angle.

Calculate how far the ball should travel in part B. SHOW YOUR WORK. Determine the percent error from the measured value of the distance traveled. Solution =0.97 S Distance traveled by the ball is given by Thus the distance is =26.68 m Percentage error = (3) If the velocity in Part A is increased, will the ball reach the ground in a time greater than, equal to, or less than the time you calculated? Explain your answer with no calculations. Solution If the velocity is increased, the time taken for the ball to reach the ground will be more than the calculated speed.

Considering the velocity equation, it’s clear that velocity is directly proportional to time thus an increase in velocity consequently increases the time. (4) If this experiment is taken to the moon (g = 1.6 m/s2), calculate how far the ball would go in Part B using the velocity from Part A. Solution V=32.27 a=1.6 m/s2 t= 0.97 S The distance traveled by the ball = (32.27*0.97) + (0.5*-1.6*0.97) =31.3019 + -8.56928 =30.54918 m Thus the distance the ball will travel on the moon is 30.

54918 meters. (5) Look at the trajectories below. Which trajectory has the longest hang time? Explain clearly. A B C Solution Trajectory labeled C has the longest hang time. This is because the distance traveled by the projectile is longer as compared to the other two i.e. A & B since the distance traveled is directly proportional to hang time. Conclusion The experiment was successful since from the measured distance, it was possible to calculate both the time and the velocity of the projectile.