Nobody downloaded yet

# Thermodynamics and fluids mechanics - Lab Report Example

Comments (0) Cite this document
Summary
This can be seen clearly from the graph where the three graphs are of straight lines coming from the origin. As the volume of the water collected reduces, the jet momentum…
Read TextPreview

## Extract of sample "Thermodynamics and fluids mechanics"

Download file to see previous pages The corresponding force F, can be found by taking the moment about the pivot of the jockey. The distance y, is the position of the jockey. Momentum was found by multiplying Mass Flow Rate by the Velocity of the vane.
As before, the corresponding force F, was found by taking the moment about the pivot of the jockey. The distance y, represents the position of the jockey. Similarly, Momentum = Mass Flow Rate multiplied by the Velocity of the vane.
As before, the corresponding force F, was found by taking the moment about the pivot of the jockey. The distance y, represent the position of the jockey. Similarly, Momentum = Mass Flow Rate multiplied by the Velocity of the vane
The only difference that is evident is only in the use of characters, otherwise, the formulas are just the same. U in the theory equation represents initial velocity just like the v in the experimental equation. While a represents the acceleration force (gravitational force) and s the distance covered (Cengel & Cimbala, 2009). The major difference between the theory and experiment performed is on the values obtained. For example, some values were not consistent as expected and while plotting the graph, the points were expected to be in a straight line, which was not the case. A line of best fit was drawn in order make the line straight.
Inaccuracy of the graph and wrong data manipulation were due to some sources. The sources of errors could have been due to incorrect timing. When determining the time interval, it could have been difficult to determine the correct interval. Another source could have been due to the incorrect measurement of volume of water collected. This could have brought wrong Mass Flow Rate hence giving wrong Momentum.
For the case of hemispherical vane, the velocity of the water jet leaving the vane was the same as that hitting it. From the data of the first trial, the velocity leaving was found to be ...Download file to see next pagesRead More
Cite this document
• APA
• MLA
• CHICAGO
(“Thermodynamics and fluids mechanics Lab Report Example | Topics and Well Written Essays - 1000 words”, n.d.)
Thermodynamics and fluids mechanics Lab Report Example | Topics and Well Written Essays - 1000 words. Retrieved from https://studentshare.org/engineering-and-construction/1683384-thermodynamics-and-fluids-mechanics
(Thermodynamics and Fluids Mechanics Lab Report Example | Topics and Well Written Essays - 1000 Words)
Thermodynamics and Fluids Mechanics Lab Report Example | Topics and Well Written Essays - 1000 Words. https://studentshare.org/engineering-and-construction/1683384-thermodynamics-and-fluids-mechanics.
“Thermodynamics and Fluids Mechanics Lab Report Example | Topics and Well Written Essays - 1000 Words”, n.d. https://studentshare.org/engineering-and-construction/1683384-thermodynamics-and-fluids-mechanics.
Comments (0)
Click to create a comment or rate a document

## CHECK THESE SAMPLES OF Thermodynamics and fluids mechanics

### Thermodynamics

...Insulated Pizza Delivery Bags Thermodynamics, the study of energy and its transformations, has a set of four laws that govern the behavior of energy.Scientists have theorized that energy can be exchanged between physical systems as heat or work. They also put forward the existence of a quantity named entropy which can be defined as an isolated system that is in thermodynamic equilibrium. On the microscopic and subatomic level an isolated system as insulated pizza bags contains particles whose motion defines its properties, The first law of thermodynamics: 'The internal energy of an isolated system is constant.' Therefore the internal energy of the content of the pizza bag remains...
2 Pages(500 words)Assignment

### Thermodynamics

...Experiment on Linear Heat Conduction INTRODUCTION Heat Transfer is the phenomenon of exchange of thermal energy from one physical system to another.Heat transfer takes place via three mechanisms viz. Conduction, Convection and Radiation. Conduction takes place by the transfer of heat energy between stationary particles adjacent to each other. Convection takes place by the transfer of heat energy by the flowing matter and as such is observed in fluids (liquids and gases). Radiation or Thermal Radiation is the process of transfer of heat through radiation or electromagnetic waves and is independent of medium. It is a common observation that when a hot body is brought in contact with a cold body, transfer of...
7 Pages(1750 words)Lab Report

### THERMODYNAMICS

...the following assumptions: • Air is behaves as an ideal gas; • Potential energy changes can be neglected across the diffuser; and • The diffuser operates adiabatically. Note1: Ensure you refer to Figure 6-22 (page 199) in the text book for a “tip” clarifying the equivalence of J/kg and m2/s2 units. You will need this to ensure the units are equivalent between enthalpy and kinetic energy in your solution within this problem)! Note2: You can solve this problem either using constant specific heats or variable specific heats. You should know the difference between the two solution methods, even though you are required to use only of these methods (not both) in your solution. a) Apply the first law of thermodynamics and...
4 Pages(1000 words)Speech or Presentation

### Thermodynamics

...flywheel being brought to a stop by a brake. The First Law of Thermodynamics primarily states that there is no way that energy can emerge out of creation nor be given to destruction for it can only be transferred between systems or be changed from one form to another. For instance, a rotating flywheel in motion possesses a ‘rotational energy’ which may also be treated a kinetic energy. Once a brake is applied to stop it, then the flywheel comes to rest the moment its kinetic energy is converted to potential energy which the device stores from the previous state of motion. Q1.3b If a fluid is at rest in a tank, does it have internal energy? First of all, an internal energy of a...
5 Pages(1250 words)Speech or Presentation

### Thermodynamics Paper

... of Learning: Thermodynamics Paper In general a phase diagram demonstrates the variations between different states of element matter in regards to their response to pressure and temperature. This paper is aimed at closely analyzing the pressure- temperature phase (P-T) diagrams of both water (H2O) and carbon dioxide (CO2). In addition to this paper illustrating the phase diagrams, it will go deeper into evaluating all the possible phase changes that this pure substance can make at atmospheric pressure. Lastly, the paper will discuss the Common applications of these phase changes. Phase diagrams plots pressure (normally in the atmospheres) against temperature (classically in degrees Celsius). With most substances, the temperature... they are...
2 Pages(500 words)Essay

### Thermodynamics and Fluids II

...for air (O2) = 11/13 =0.8462 Mass fraction for octane =2(30)/[2(30)+11(32)] =0.1456 Mass fraction for air (oxygen) =11(32)/[11(32)+2(30)] =0.8544. Air –fuel ratio is = (11*4.76)/2 =26.18kmol (air)/ kmol (fuel). Question 2 According to Chih, Rankin cycle is thermodynamic cycle which converts heat from steam into work. It does not involve any internal irreversibility and consist of the following four processes. 1-2 isentropic compression in a pump 2-3 Constant heat addition in the boiler. 3-4 isentropic expansion in a turbine. 4-1 P=Constant heat rejection in the condenser. It is assumed that the components of the...
2 Pages(500 words)Essay

### Thermodynamics

...ASSIGNMENT FACULTY OF: APPLIED DESIGN AND ENGINEERING OF PROGRAMME: BEng YEAR OR LEVEL: Year OF MODULE/UNIT/EXAM PAPER: Engineering Science II Thermodynamics Date set: 12th March 2014 Date to submit: 1sr May 2014 QUESTION ONE (25 marks): Closed system A well-insulated piston-cylinder device contains 5 L of saturated liquid water at a constant pressure P of 175 kPa. Water is stirred by a paddle wheel while a current of 8 A flows for 45 min through a resistor placed in the water. One-half of the liquid is evaporated during this constant-pressure process and the paddle-wheel work amounts to 400 kJ. Notes: Kinetic and potential energy changes are negligible. For a constant-pressure process, the boundary work is given... negligible...
8 Pages(2000 words)Essay

### THERMODYNAMICS AND FLUID MECHANICS

...of individual characteristics depicted by the pressure-energy, potential-energy, and kinetic-energy terms that constitute the Bernoulli’s equation. It may be observed that the HGL almost assumes the same shape and slope of EGL just as the left-hand side of the Bernoulli’s equation merely reflects or mirrors the terms present at the right hand side of it. The difference between the HGL and the EGL signifies ‘head losses’ that correspond to change in the state of pressure, velocity, and fluid level that altogether appear in the Bernoulli’s equation. Solution: The head loss / pressure loss consists of 5 different parts as follows: Resistance in 30-mm pipe = = = 1.2241 * 106 Resistance in 60-mm pipe ...
6 Pages(1500 words)Assignment

### Thermodynamics and Fluid Mechanics

...OF SUNDERLAND DEPARTMENT OF COMPUTING, ENGINEERING AND TECHNOLGY EAT106 – THERMODYNAMICS AND FLUID MECHANICS REFERRED WORK 2014 NAME: DATE: Question 1 Water at 50 degrees Celsius flows at a mass flow rate of 20 kg/s in a 200 mm diameter pipeline. a) Find the density and dynamic viscosity of the water at this temperature letbe the dynamic viscosity (kg/ms)= {[2.414 x 10-5)] x[10(247k/(temp-140k))]} ={[2.414 x 10^-5)] x [10(247k/(50 + 273 -140))]} =0.00002414 x 101.4 =0.000605914kg/ms  =6. 091 x 10^ -4 kg/ms Density=988.1kg/m3 (Source Engineeringtoolbox.com, 2014) b) Calculate the velocity of the water. Q=AV V=Q/A Volume flow rate= {(mass low rate)/...
3 Pages(750 words)Coursework

### Thermodynamics and Fluids II Laboratory tests and report

...of the flow. The speed of airflow is determined when there is change in pressure between the two holes found in the Pitot tube; known via head (Kundu, Cohen and Dowling, 2012). Therfoe the speed of airflow is calculated using Bernoulli’s equation: v = velocity of airflow (m/s) =density of air p= change in pressure (N/m2) . Static Tube The Static pressure is normally “half” that of Pitot tube; when determining the static pressure there should be known air flow resistance. Figure 5. Static Tube When Bernoulli’s equation is obtain between 2 and 1 then;  +  + =  +  +  = = = (m/s) =g (N/m2) Aim The purpose of this laboratory was to analyze jet pumps using knowledge of fluid...
5 Pages(1250 words)Lab Report
sponsored ads
We use cookies to create the best experience for you. Keep on browsing if you are OK with that, or find out how to manage cookies.

## Let us find you another Lab Report on topic Thermodynamics and fluids mechanics for FREE!

This Website is owned and operated by Studentshare Ltd (HE364715) , having its registered office at Aglantzias , 21, COMPLEX 21B, Floor 2, Flat/Office 1, Aglantzia , Cyprus.
Join us:
Contact Us