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Statistics: Project Questions School Affiliation Statistics: Project Questions Question Mean of API= 165.49/13= 12.73 Variance= 15,818.46- 15563.08= 255.38/12= 21.28 Standard error= 0.035 Z-score of 95% confidence = 1.96 but Z= (x-mean)/standard deviation Price= 0.976×0.035+12.73= 12.8 Question 2 95% confidence= Z0.05= 1.96 Mean oil price= 165.49/13 = 12.73 Variance= 1/n-1(x-mean) 2 1/12(2109.1937-2106.6877) = 0.2088 s.t = 0.20881/2/13= 0.035 z= (x-u)/s.t where s.t is the standard error. Lower limit= 12.73- 1.96×0.035= 12.6614 Upper limit = 12.73+1.96×0.035= 12.7986 Confidence region for the mean= 12.
66≤x≤12.7986 Question 3 The interval for x is narrower than the interval for y since the standard error is small Question4 Predicted values of y given the regression equation y= 9.4349+0.095235x, replacing values for x and solving for y we get the predicted values of y to be Predicted values residual values 10.58 16.42 10.58 17.92 10.61 20.19 10.60 20.7 10.62 21.28 10.64 23.86 10.65 23.35 10.67 24.03 10.67 26.33 10.69 30.31 10.69 30.31 10.69 28.11 10.7 28.
6 Question 6 A graph of residual values against the predicted values Question 7 Heterosdacity is a problem since there is a wider variability between the two variables in the scatter diagram. I.e. as the independent variable increases the gap, hence, makes it difficult to analyze the data. Question 8 Question 9 Standardized residuals are values divided by their standard errors Standard erro= 0.35 and dividing we get the following values 46.91 51.2 59.14 60.8 68.17 66.71 68.65 75.23 86.6 86.6 80.31 81.71 Question 10 Possible outliers 30.31, 30.31, 28.11, 28.6
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