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Health Statistics Number Question 7 Diagnosis A B C 1 11, 7, 9 8, 6, 7 5, 4, 72 14, 10, 11 10, 9, 8 6, 8, 73 4, 5, 3 5, 5, 6 3, 4, 24 10, 9, 7 6, 7, 4 5, 6, 3If α= 0.05, determine whether differences among the treatment, block, and interactive effects are significant.SolutionDiagnosisABC1118576497721410610981187345355436241065976743ANOVA: Two-Factor With ReplicationSUMMARYABCTotal1 Count3339Sum27211664Average975.3333337.111111Variance412.3333334.3611112 Count3339Sum35272183Average11.66667979.222222Variance4.333333115.6944443 Count3339Sum1216937Average45.333333334.111111Variance10.333333311.6111114 Count3339Sum26171457Average8.6666675.66666674.6666676.333333Variance2.3333332.33333332.
3333335Total Count121212Sum1008160Average8.3333336.755Variance10.424243.11363643.454545ANOVASource of VariationSSdfMSFP-valueF critSample120.3056340.1018520.922716.97287E-073.008787Columns66.72222233.3611117.40582.13294E-053.402826Interaction20.6111163.4351851.7922710.1432913562.508189Within46241.916667Total253.638935 On this first section of analysis, the mean of these samples is 9, 7, and 5.333 days for diagnosis 1 while the overall mean all the patients for diagnosis 1 is 7.111days. At the last part before the ANOVA table, each physician’s mean length of delay is reported as follows, A= 8.
333 days, B=6.75 days and C=5 days.The ANOVA TableFrom these ANOVA table above, one can conclude that MS (ERROR) and MS (B) differ significantly because P-value=0.000000697 which is a figure less than alpha value of 0.05. Thus the null hypothesis can be rejected. Moreover, the table shows that the probability of calculated F=17.40 is 0.00002. This probability 0.00002 is less that α=0.05, which shows that the value of MS treatment is significantly bigger than MS ERRORS. Therefore these results indicate that the differences existing among the physicians contribute to the delay experienced in treating patients.
ReferenceBroyles, R. W. (2006). Fundamentals of Statistics in Health Administration. New York: Jones & Bartlett Learning.
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