Calculations on Horsepower - Lab Report Example

The coefficient of static friction is calculated by Tan θ where θ is the angle of inclination.
Therefore Tan 17.46 = 0.3145.
Therefore Effort is
300 = Sin17.46 + 0.3145Cos17.46
300 = 0.6
Answer = 500N

The horsepower of a slow mover can't be greater than that of a fast mover. The former undertakes the activity with low rates whereas the latter does the same activity with higher rates of power (Walsh, 2007).

Person A is a slow-moving student having an average time of 7.10 seconds, 133.69 watts and 0.18 horsepower. Person B is also a slow-moving student as reflected by an average time of 8.41 seconds, 212.84 watts and 28.33 horsepower. Person C can also be categorized as a slow-moving student as evidenced by an average time of 5.80 seconds, 373.24 watts and 0.49 horsepower.

Person A is observed to be a fast-moving student as evidenced by an average of 5.33 seconds on time, 175.56 watts and 0.23 horsepower on power. Person B is also a fast-moving student because he/she uses the lesser time of 6.41 seconds, 279.5 watts and 0.38 horsepower on average. Person C can be attested as a fast mover hence the average of 4.45 seconds, 455.72 watts and 61 horsepower on average.

Person A in Table 1 does the activity with a lesser rate as compared to Person A in Table 2 who uses higher rates. Person B in Table 1 also undertakes the activity with lower rates as opposed to Person B in Table 2 who does it with higher rates. Person C in Table 1 is also observed to use a lesser rate when doing the activity, unlike Person C in Table 2 who uses higher rates.