Concerning Determination of Resistance - Lab Report Example

Rtotal = 40 Ω

2-2

40 Ω + 10 Ω= 50 Ω

2-3

For sections 2-1, Rtotal is 40 Ω while for 2-2, Rtotal is 50 Ω.

2-4

VRtotal = 7.9 V, VRtotal = 7.9 V and VRtotal = 7.9 V

They are all equal because the voltage drop on parallel resistors should be the same.

2-5

The voltage across the 10 Ω is 2V. Which is almost equal to 10 - 7.8= 2.1 V which is about 2V.

2-6

Itotal= 0.2 A, IR200=0.04A, IR100=0.08A, IR100=0.08A,

(0.04+0.08+0.08)= 0.2 A

2-7

Rtotal = 1 Ω

Rtotal 2 = 4 Ω

Itotal =

I3=I4 =

2-8

Rt= 0.545 Ω

It = Ω

I3Ω = A

2-10

Rtotal= 0.545455 Ω + 1 Ω = 1. 545455 Ω

I total=

Vparallel =  

I3 Ω =

2-11

Rtotal=

Itotal =

Vparallel = 0.85   0.55 = 0.47V

I3 Ω =

2-12

R1=

=

R2=

Rtotal=

I total=

V= I.R = 2.3 * 0.55 = 1.27 V

I3.0 = 

2-13

Yes. This is because it is a parallel circuit and therefore it has a reduced resistance.

3.2

I=

3-3

I=

3-4

RDMM= VDMM ()

3-5

RDMM=

Rearranging the equation

RDMM=

3-6

= 9.05 mΩ

DISCUSSION AND CONCLUSION

From the experiment, the resistors did not behave like ohmic resistors because from the graph of V against I the slopes did not pass through the zero intercepts. This may have been due to some technical problems with the DMM.