## CHECK THESE SAMPLES OF Statistics assignment

...?Running head: HOURS WORKED PER WEEK Effect of Gender, Work Status and Age on Hours Worked per Week July This study analysed the effect of gender, work status and age on number of hours worked per week in job along with relationship between individuals work status and their gender. The analysis was performed using the 2006 Northern Ireland Life & Time Survey data. The **statistical** methods used for the analysis were Independent-Samples t-Test, Analysis of Variance (ANOVA), Chi-Square Test of Independence and Correlation. The results suggested significant effect of gender and individual work status on number of hours worked per week in job, however, age have no significant effect on number of hours worked per week in job....

12 Pages(3000 words)Assignment

...1. A research is usually meant to study the characteristics of a population. However, the size of a population in most cases is so large that it is not possible to gather all the relevant information on all population units. Rather it is a much more convenient option to collect a sample from the population and conduct a similar research on it and later check the significance of the results so obtained.
2. A simple random sampling refers to the case where a sample is drawn at random from the population and a research is conducted on it. On the other hand, stratified sampling implies the same research when conducted after dividing the total sample into various strata and then considering each individual result as one of the inherent...

3 Pages(750 words)Speech or Presentation

...then be computed as follows:
Based on these parameters, it is then possible to determine whether the advertized mean differs from the actual mean.
Hypotheses:
H0: The advertized mean is the same as the actual mean.
H1: The advertized mean differs from the actual mean.
Degrees of Freedom:
From the t-distribution table, the corresponding critical value for two tails at 90% confidence is 1.761.
Decision Rule:
Reject H0 if 1.761
Calculations:
Conclusion:
Since 1.761, H0 is rejected. At 90% confidence, there is sufficient evidence to support that the advertized and actual mean life times differ.
Answer 9
At a sample size of 23, it is appropriate to use the t-distribution in place of z-scores. Since the relevant sample...

13 Pages(3250 words)Speech or Presentation

...for p is;
p±Z∂α where Z = 1.96 (95%) and ∂α is the proportion test **statistic**
∂α = ,
=.04± (1.96* {[(.37*.63)/100]+ [(.41*.59)/100]}1/2
= .04±1.96*0.069
=.04±0.135
Considering each alone,
Leaflets alone
=.37±1.96 {(.37*.63)/100}1/2
=.37±.095
For the discussions group
=.41±1.96 {(.41*.59)/100}1/2
=.41±.096
This means that the proportion of improvement of those that participated in the discussions and group exercise overlap the proportion of improvement of those that did not. This means that participating in group discussions and exercises is beneficial in reducing chronic back pain than receiving leaflets alone. The interval, .04±0.135 indicates that the impact of discussions and group exercises has a proportion...

4 Pages(1000 words)Essay

...**Statistics** 302 **Assignment** 2 Report written by: Number: ”I confirm that I have not received help from, or given help to, anyone else in constructing the
solution to this **assignment**”
______________________
Name
Q1. (10) The number of UBC students infected by H1N1 is a Poisson random variable with rate 5 per week.
(a) What is the probability that there are more than 10 students infected in a week?
Solution:
The poisson probability is given by:
p(x; μ) = (e-μ) (μx) / x!
The probability that more than 10 students are infected in a week =
P(x>10, μ = 5) = e-(5) * [(511)/11! + (512)/12! + (513)/13! + … + 5^20/20! +..]
P(x>10, μ = 5) = e-(5) * 2.0325
P(x>10, μ = 5) =...

2 Pages(500 words)Statistics Project

...Maths and **Statistics** - **Assignment** #2 Q a) The arc of a circle with a radius of 5cm is subtended by an angle of 24o. What is the length of the arc? What is the area of the sector? (Hint: first convert to radians)
Radius, cm
Angle,
Angle in Radians,
Length of an arc is given by
Therefore,
≈ 2.09 cm (2d.p.)
The length of the arc is about 2.09 cm.
Area of a sector is given by
( in radians)
Therefore,
≈ 5.25 cm2 (2d.p.)
The area of the sector is about 5.24 cm2.
(b) In the diagram below the line AB is a tangent to the circle of radius x.
What is the radius of the circle? (Hint: find out the definition of a tangent)
A tangent to a circle is a straight line that touches the circle at only one...

4 Pages(1000 words)Essay

...is p.
However, if receiving a jolt of electricity on one-occasion affects the following occasions than probability (p) will not remain the same for other occasions (because Charlie will be not alive for following occasions). In that circumstance, the probability that Charlie receives the life-ending shock on that last nth insertion will be.
5. n = 100, = 7 years and s = 2 years
a. The null and alternate hypotheses are
(Mean has not changed from the value of 7.5 years of 20 years ago)
(Mean has changed from the value of 7.5 years of 20 years ago)
The test is two-tailed test.
b. The test **statistic** is
c. The p-value for the test is 0.0124.
p-value = 2 * P(z < -2.50) = 2*0.0062 = 0.0124
Decision: Reject null hypothesis,...

1 Pages(250 words)Speech or Presentation

...those who didn’t do the extra credit tests (**assignment**) scored least (M= 7.54, SE= .19). The significance criterion is shown by p= .002 ( Leech & Morgan,2005). This significance shows the importance of students to sitting for extra credit tests. It makes them ready and well prepared for the final exam. It can also be used by the administration and parents in convincing the students on the importance of extra credit tests.
References
Green, S. B., & Salkind, N. J. (2003). Using SPSS for Windows and Macintosh: Analyzing
and Understanding Data (3rd ed.). Upper Saddle River, NJ: Prentice Hall.
Leech, N. L., & Morgan, G. A. (2005). SPSS for Intermediate **Statistics**: Use
and Interpretation (2nded.). Mahwah,...

2 Pages(500 words)Research Paper

...and the claim is to be a true one whereas the null hypothesis is that the perceived quality of merchandise is a not a determining factor of store image for shoppers at.
(ii) Answer:
The pooled sample proportion is
p=(n1p1+n2p2)/(n1+n2)=(0.74*350+0.52*500)/(350+500)=(259+260)/850=0.611
(iii) Answer:
If the test **statistic** is 6.474, the p value for one tailed test is almost 0. It is given by p=3.16001E-10=0.000000000316
2. a. Answer:
The minor problem may be due to the expected frequency of Unspecified for male is less than 5. Since for applying Chi Square test each cell expected frequency should be minimum 5 to maintain the continuity of Chi Square. But this is violated. So only the unspecified data is not included.
b...

5 Pages(1250 words)Statistics Project

... Chapter 6 &7 Answers C 2. A 3. A 4. B 5. C 6. B 7. A 8. B 9. B 10. C Question 22. r= r 10x 353 -55 x 59)/{(10x415)-552}1/2x {(10x 384)-592}
= 285/33.5410 x18.9473
= 285/635.5112
= 0.45
r= 0.45 indicates that there is a low positive correlation between mood and creativity.
Predicted creativity would be the average creativity score for all participants that is 59/10= 5.9.
Standard deviation= 1.78
The error would be + or – 1.78
Regression model y=a + bx
a =
= (59- 0.79x55)/10
=1.56
Slope b= (Roger,73)
= (10x 353-59x55)/(10x415-592)
= 190905/241369
= 0.79
and x =3
Y= 1.56 +0.79 x 3
Ý=3.93
The error would reduce using the regression analysis by 1.97
Question 23
The **statistics** to be used... the...

1 Pages(250 words)Assignment