Geometry - Speech or Presentation Example

Step Draw a line AB that we will be divided into 3 (in this case) equal parts. From point A, draw a line segment at an angle to the given line, and about the same length. The exact length is not important.Set the compasses on A, and set its width to a bit less than one third of the length of the new line.Step the compasses along the line, marking off 3 arcs. Label the last one C.With the compasses width set to CB, draw an arc from A just below it.With the compasses width set to AC, draw an arc from B crossing the one drawn in step 4.

This intersection is point D.Draw a line from D to B.Using the same compasses width as used to step along AC, step the compasses from D along DB making 3 new arcs across the lineDraw lines between the corresponding points along AC and DB.Done. The lines divide the given line segment AB in to 3 congruent parts.Question2The new line is. But X= |AB|/3 or 3x=|AB|Using the right angled triangle 3:4:5 we can use the relation of the right angled triangle to obtain the line. Using the right angled rule let the original line and the new line be the two short side.

Let |AB| take the ratio 4 while . Take the ratio 3. This mean that |AB|=4, while = 3. From this we get that  = |AB|/4. Implying that the line . Can be obtained by dividing the line AB into 4 equal parts. Question 3The line |AB| is 3x. let the right angle triangle be 3:4:5. The new line is given as . If we let 4 = |AB|, and 3 to be equal to the new line . we cube the line AB which will have the length . This means that 4= , while 3 is equal to the new line . Implying that the new line can be obtained by dividing the cube of the new line by 4 Draw the new lines