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Probability Application - Essay Example

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Summary
The paper "Probability Application" assumes that someone calls and the last card are dealt. The player starts off by evaluating all possible outcomes. For each player, it's recommended to pick the winning hands from the possible outcomes and group them accordingly…
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Probability Application
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Extract of sample "Probability Application"

These probabilities help me evaluate the chance of losing all my cash in case I call the $10,000 bet and ultimately, the decision that I will make.
Assuming I call the $10,000 bet, there are 44 possible outcomes but in the end, they will result in five distinct winning-hands (a draw is not possible in this game).

Four of a kind: The opponent’s possible best hand will occur if the last card dealt is a 10 of hearts giving him four tens. The probability of this win is:
P=Pr⁡(10 of hearts)

P=1/44
Full house: The opponent gets a Full-house provided that a three, four, or nine is dealt. For him to win, neither a straight-flush nor a four kind should occur. The probability of this win is:

P={Pr⁡(a three)+Pr⁡(a four) + Pr(a nine)} * Pr(not a four-kind)
P=(3/44+3/44+3/44)*43/44=387/1936

Flush: I will hold a flush if a diamond is dealt. To win with the flush neither of the above hands occurs. The probability of winning with the flush is:
P=Pr(diamond)*Pr(not full house)*Pr(not four of a kind)
P=(7/44*43/44*1549/1936)=0.12440

Straight: I will hold a straight hand if an eight is dealt. To win with the straight neither of the above hands occurs. The probability of winning with the straight is:
P=Pr(eight)*Pr(not flush)*Pr(not full house)*Pr(not four of a kind)
P=(3/44*43/44*1549/1936*0.87560)=0.04668

Three of a kind: The opponent will hold a three of a kind if all the above cards are not dealt. The probability of winning with three of a kind is equal to the probability of the above hands not occurring, given by:
P={Pr(not straight)*Pr(not flush)*Pr(not full house)*Pr(not four of a kind)}
OR: P=1-{Pr⁡(straight)+Pr⁡(flush)+Pr(full house)+Pr(four of a kind)}
P=1-(0.04668+0.12440+387/1936+1/44)=0.60630

My total probability of winning is: 0.12440+0.04668=0.17108
My opponent’s probability of winning is: 0.60630+387/1936+1/44=0.82892
I have a 17% chance of winning against my opponent’s 83%. I, therefore, have a higher chance of losing than winning in case I match the opponent's $10,000 bet. The best move is to fold and keep the $10,000 as opposed to calling. Read More
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