We evaluated the traffic offenders imprisonment in Australia, we subjected the analysis one-simple t test and using a hypothesized mean value of 16.7 at a significance α = .05. Assuming an equal mean variance ; the sample mean = 17.8 (SD = 6.0) is statistically significantly…
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One mean t-test was conducted to evaluate whether the Americans drive the same mean distance as in 2005. With a sample N = 500 , with a sample mean 11.8, t =-2.23, p = .03 at a significance level α = .05 with a variation of SD 6.00; thus the test is statistically significant at a hypothesized mean value of 12.4. Thus we can assume that with equal mean variance test the evaluation is significant, and at 95% CI [ 11.3, 12.3], the distance mean fall within the parameter of the CI. We accept the null hypothesis that American’s still drive the mean distance like
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Minitab Assignment Example | Topics and Well Written Essays - 500 words - 5. Retrieved from https://studentshare.org/statistics/1693532-minitab
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Minitab Assignment Example | Topics and Well Written Essays - 500 Words - 5. https://studentshare.org/statistics/1693532-minitab.
“Minitab Assignment Example | Topics and Well Written Essays - 500 Words - 5”, n.d. https://studentshare.org/statistics/1693532-minitab.
From the graph, it there seems a linear relationship between the two variables as shown below. 2. Equation of the "Best Fit" Line for Relationship between CREDIT BALANCE and SIZE In next step, regression model was determined between Credit Balance and Size using the Regression Analysis in Minitab.
Is there evidence to suggest that mean has changed?
iv) Perform a hypothesis test to see whether the mean number of male cattle is equal to the mean number of female cattle. To three decimal places, what is the p value from the test? Is there evidence to reject the null
Then the model fit can be checked using the F-test. It is also important that the right model is selected in the beginning.
c) The variability of this data would be looked into by first calculating the standard deviation for each level of absorbance with
The p-value is given as 0.000 (a value less than α=0.05); we thus reject the null hypothesis and conclude that there is significant difference in the proportion of those who gave the right answers and those
Do not perform any calculations; MINITAB has done them for you! Just find the values of the test statistic and the p-value on your Minitab output. State your conclusion using words relevant to the problem.
1. When public opinion surveys
Based on the results provided by the author, it is evident that more money was spent on newspaper advertisements than was spent on radio advertisements. Since he rejected the null hypothesis, he concludes that indeed the expenditure made on radios was significantly different from that made on newspapers.
Do you think the sample would have been randomly selected from this target population? Explain your answer. Yes. Every person in the city has an equal chance of being selected.As a result the random sampling will not be biased (Sweeney, et al., 2011, pp. 142-145)