Conservation of momentum - Lab Report Example

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V=x/t=x/√(2y/g) = x√(g/2y) = 2.631√(9.8/2x0.847) = 6.328m/s The muzzle velocity calculated by equation 9 is almost half that calculated by equation 6. This is due to the errors during the experiment. In this experiment, obtained values were not the exact theoretical values…
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Conservation of momentum
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Download file to see previous pages During the experiment one should ensure that at least three readings for a particular step are taken then an average of the reading obtained so as to minimize the errors of parallax. The experiment needs to be done at least twice to confirm the recorded values and minimize the errors. The stop watch and all the apparatus used for the experiment needs to be observed before the beggining of the experiment to ascertain their efficiency. The experiment could also be done in an area with vacuum conditions in order to minimize the interferences in obtaining the readings due to air resistance. The two values for V obtain in part 1 and part 2 are not as close as they are expected. This is so due to the errors during the experiment. Without errors, the two values of velocity should be the same. Reanalyzation of the tale values using the largest h fails to make any significant change in the final results of v (Susan 10). The fact is that the two values fail to be as close as they are expected to be. However repeating the entire experiment while avoiding the experimental errors may give out values that are close to the theoretical ...Download file to see next pagesRead More
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