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Organic chemistry - Essay Example

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Due to the strength of this bond the absorption peak is at a higher intensity. The absorption peak at 1716 per cm at the spectrum…
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Organic chemistry
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Organic chemistry

Download file to see previous pages... A careful look at the peaks results displayed by the NMR of the substance is also required. A singlet peak at a chemical shift value of 11.1ppm confirms the presence of the COOH group. Peak at 2.4ppm is due to the presence of the group R-C=O attached to CH. Applying the n+1 rule we know that the methylene or the CH2 group will be able to interact with the three hydrogen of the methyl or the CH3 group, hence (3+1)=4 peaks or a quadruplet is obtained. Similarly the three hydrogen atoms of methyl are ale to interact with the 2 hydrogen of methylene, hence (2+1) =3 or a triplet peak is displayed. The ratio obtained is determined by the relative heights of the respective peaks.
Peak at 3330 per cm at the infra red spectrum is due to the high absorption range of the O-H group in the compound, whereas peaks centered at 2900 per cm is due to the presence of C-H bonds in the compound.
M-1 peak of 60 is the RMM of the compound (12*3) + (1*8) + 16= 60 atomic mass unit, peak at 31 confirms the presence of CH2OH: 12+2+16+1=31, C2H3 gives peak at 27: (12*2) + (1*3), C3H7O :( 12*3) + (1*7) + 16=59.
3.6ppm value at the NMR suggests the presence of R-OH functional group. The single hydrogen is able to interact with the neighboring hydrogen of the CH2 group hence a triplet is obtained. A singlet peak at a chemical shift of 2.2ppm shows the presence of the R-C-O fragment. 6 peaks at 1.6ppm are obtained due to the presence of R3CH where single hydrogen is able to interact with 5 neighboring hydrogen giving 6 peaks. Triplet of 0.9ppm is present due to R-CH3 as three hydrogen interact with the neighboring 2 of the CH2 giving a triplet peak (2+1). The ratio of 2:1:2:3 provides us the different environments of the protons.
Percentages of carbon, hydrogen and an unknown element are 45.9%, 8.9% and 45.2% respectively. Dividing them by their respective relative molecular masses 45.9/12, 8.9/1 and 45.2/35.5, it is found out that the other element is chlorine as the percentage ...Download file to see next pagesRead More
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