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# Probability - Speech or Presentation Example

Summary
I would continue with my two down cards 6 of (diamonds) & 7 of (diamonds) bearing in mind that they will come up.
Probability does not always occur twice, so…

## Extract of sample "Probability"

PROBABILITY Explain your strategy for solving the problem I will not call my opponents bet by tossing the rest of my money because in playing cards winning lies on probability. I would continue with my two down cards 6 of (diamonds) & 7 of (diamonds) bearing in mind that they will come up.
Explain why your strategy will work.
Probability does not always occur twice, so there is no need for quitting. My strategy therefore largely lies on probability. Probability is always related to gambling because if at all one of the down cards does not show up there is a high possibility that they will come up in the next play (Bassarear 2011).
So am having the values diamonds=6, 7= the possibility 6/48, 7/48
After showing of the cards, the following are the probability= 6 diamonds occurring= 6/48
= 3 diamonds occurring= 3/48
7 diamonds occurring= 7/48
From this calculation, there is little possibility, (3 of 52,) of three coming up again. Probability also do not repeat itself and therefore the probability of three coming up again is still little if reasoning from the same line of thought. This therefore supported my need to continue playing because I knew my down cards could come up instead of the three of diamonds.
The possibility of 4 flower coming up again is nil, because the 4 only occurs once.
The possibility of the 9 coming up again is also nil
The possibility of 10 diamonds coming up again is nil.
This therefore applies that the next tossing will not be dependable on the previous tossing. Hence my strategy for continuing with the play
My opponent showing up the two (10) will serve to hold no effect on whether I will need to play again, because we are on the same ground where we both hold the same probability. Having the 10 flower does not hold that he is near the possibility of getting the 10 (diamonds).
Because of the probability, I had another chance of tossing again, because at the beginning of the game the possibility of one winning is always zero. Zero, meaning I was still in a position of winning the game.
Reference
Bassarear, Tom. 2011. Mathematics for Elementary School Teachers. Cengage Learning. Read More
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