The Field of Survey Engineering - Statistics Project Example

Survey Name Course Instructor Date Levelling Control Survey (Task 1) The levelling run will bring in “vertical control” for the propose path, that is levels, from a nearby bench-mark to several areas of the site. BS FS REMARKS 2.252   BM 0.945 0.41 A3 0.419 2.142 MH 0.898 2.822 L5 1.111 3.283 CP 2.447 3.233 B3 3.622 0.947 SMS 2.52 1.055 L3 1.922 0.697 L2 0 1.499 BM Sum the back sights and fore sights   BS FS Rise Fall RL Remarks   2.252         BM   0.945 0.41       A3   0.419 2.142       MH   0.898 2.822       L5   1.111 3.283       CP   2.447 3.233       B3   3.622 0.947       SMS   2.52 1.055       L3   1.922 0.697       L2   0 1.499       BM SUM 16.136 16.088                       difference   -0.048         Calculate the rises and falls   BS FS Rise Fall RL Remarks   2.252         BM   0.945 0.41 1.842     A3   0.419 2.142   1.197   MH   0.898 2.822   2.403   L5   1.111 3.283   2.385   CP   2.447 3.233   2.122   B3   3.622 0.947 1.5     SMS   2.52 1.055 2.567     L3   1.922 0.697 1.823     L2   0 1.499 0.423     BM SUM 16.136 16.088                       achieved miscloses   0.048         Sum the rises and falls   BS FS Rise Fall RL Remarks   2.252         BM   0.945 0.41 1.842     A3   0.419 2.142   1.197   MH   0.898 2.822   2.403   L5   1.111 3.283   2.385   CP   2.447 3.233   2.122   B3   3.622 0.947 1.5     SMS   2.52 1.055 2.567     L3   1.922 0.697 1.823     L2   0 1.499 0.423     BM SUM 16.136 16.088 8.155 8.107                   difference   -0.048   -0.048     Calculate the RLS and determine difference in final RLS   BS FS RISE FALL RL REMARKS   2.252       47.921 BM   0.945 0.41 1.842   49.763 A3   0.419 2.142   1.197 48.566 MH   0.898 2.822   2.403 46.163 L5   1.111 3.283   2.385 43.778 CP   2.447 3.233   2.122 41.656 B3   3.622 0.947 1.5   43.156 SMS   2.52 1.055 2.567   45.723 L3   1.922 0.697 1.823   47.546 L2   0 1.499 0.423   47.969 BM SUM 16.136 16.088 8.155 8.107 47.921             47.969   difference   -0.048   -0.048 -0.048   Traversing (Task 2) The traverse will be used to coordinate new point “B” which will be used in topographic survey practical Traverse fieldwork data group   2014 at to Horizontal Angels vertical angels  slope dist       FL Horiz  FR Horiz   FL Vert  FR vert  A3 Y 0o 0’ 1’ 180o 0’ 8’’ 93o 47’ 2’’ 266o 12’ 49’’ 63.479 A3 X 5o 4’ 36’’ 185o 4’ 27’’ 93o 19’ 5’’ 266o 40’ 53’’ 50.283           X A3 0o 0’ 1’’ 180o 0’ 12’’ 86o 35’ 28’’ 273o 24’ 27’’ 50.288 X B3 226o 33’ 8’’ 46o 33’ 29’’ 100o 30’ 29’’ 259o 29’ 44’’ 28.927              B3 X 2o 52’ 53’’ 182o 52’ 59’’ 79o 20’ 16’’ 280o 39’ 42’’ 28.942 B3 Y 32o 4’ 17’’ 212o 4’ 24’’ 81o 26’ 46’’ 278o 32’ 59’’ 27.392             Y B3 0o 0’ 0’’ 180o 0’ 0’’ 90o 0’ 0’’ 270o 0’ 0’’ 27.101 Y A3 99o 11’ 21’’ 279o 11’ 21’’ 90o 0’ 0’’ 90o 0’ 0’’ 63.336 Horizontal Angle Reduction Transfer your horizontal angle readings to a table Traverse fieldwork data group   2014 at to Horizontal Angels Red Angle       FL Horiz  FR Horiz   Diff FR-FL Corr to FL Mean FL A3 Y 0o 0’ 1’ 180o 0’ 8’’ +7’’ +3.5 0o 0’ 9’ 0o 0’ 0’ A3 X 5o 4’ 36’’ 185o 4’ 27’’ -9’’ -4 5o 4’ 35’’ 5o 4’ 26’’     X A3 0o 0’ 1’’ 180o 0’ 12’’ +11’’ +5.5 0o 0’ 10’’ 0o 0’ 4’’ X B3 226o 33’ 8’’ 46o 33’ 29’’ +21’’ +10.5 226o 33’ 19’’ 226o 33’ 11’’       B3 X 2o 52’ 53’’ 182o 52’ 59’’ +6’’ +1.5 2o 52’ 58’’ 2o 52’ 56’’ B3 Y 32o 4’ 17’’ 212o 4’ 24’’ +7’’ +2.5 32o 4’ 20’’ 32o 4’ 22’’       Y B3 0o 0’ 0’’ 180o 0’ 0’’ 0’’ +2.5 0o 0’ 3’’ 0o 0’ 5’’ Y A3 99o 11’ 21’’ 279o 11’ 21’’ 0’’ +2.5 99o 11’ 24’’ 99o 11’ 21’’ Vertical Angle Reduction Transfer your horizontal angle readings to a table Traverse fieldwork data group   2014 at to Vertical Angels Red Angle       FL Vert  FR vert  Diff FR-FL Corr to FL Mean FL A3 Y 93o 47’ 2’’ 266o 12’ 49’’ -7o 34’ 53’’ -3o 67’ 27’’ 89o 79’ 75’ 0o 0’ 0’ A3 X 93o 19’ 5’’ 266o 40’ 53’’ -6o 68’ 52’’ -3o 34’ 26’’ 89o 84’ 79’’ 0o 5’ 4’’         X A3 86o 35’ 28’’ 273o 24’ 27’’ -3o 11’ 01’’ -1o 55’ 06’’ 84o 80’ 22’’ 0o 0’ 0’’ X B3 100o 30’ 29’’ 259o 29’ 44’’ -21o 00’ 85’’ -10o 50’ 43’’ 89o 79’ 86’’ -4o 99’ 64’’          B3 X 79o 20’ 16’’ 280o 39’ 42’’ +21o 19’ 26’’ +10o 59’ 72’’ 89o 79’ 88’’ 0o 00’ 00’’ B3 Y 81o 26’ 46’’ 278o 32’ 59’’ +7o 06’ 13’’ +3o 03’ 07’’ 84o 29’ 53’’ -5o 50’ 35’’         Y B3 90o 0’ 0’’ 270o 0’ 0’’ 0’’ 0’’ 90o 0’ 0’’ 0o 0’ 0’’ Y A3 90o 0’ 0’’ 90o 0’ 0’’ 0’’ 0’’ 90o 0’ 0’’ 0o 00’ 00’’ Horizontal Angle Reduction Transfer your horizontal angle readings to a table Traverse fieldwork data group   2014 at to Horizontal Angels     Mean FL Red Angle   slope dist A3 Y 0o 0’ 9’ 0o 0’ 0’ 63.479 A3 X 5o 4’ 35’’ 5o 4’ 26’’ 50.283       X A3 0o 0’ 10’’ 0o 0’ 4’’ 50.288 X B3 226o 33’ 19’’ 226o 33’ 11’’ 28.927       B3 X 2o 52’ 58’’ 2o 52’ 56’’ 28.942 B3 Y 32o 4’ 20’’ 32o 4’ 22’’ 27.392       Y B3 0o 0’ 3’’ 0o 0’ 5’’ 27.101 Y A3 99o 11’ 24’’ 99o 11’ 21’’ 63.336 Vertical Angle Reduction Transfer your horizontal angle readings to a table Traverse fieldwork data group   2014 at to Vertical Angels Red Angle       FL Vert  FR vert  Diff FR-FL Corr to FL Mean FL A3 Y 93o 47’ 2’’ 266o 12’ 49’’ -7o 34’ 53’’ -3o 67’ 27’’ 89o 79’ 75’ 0o 0’ 0’ A3 X 93o 19’ 5’’ 266o 40’ 53’’ -6o 68’ 52’’ -3o 34’ 26’’ 89o 84’ 79’’ 0o 5’ 4’’         X A3 86o 35’ 28’’ 273o 24’ 27’’ -3o 11’ 01’’ -1o 55’ 06’’ 84o 80’ 22’’ 0o 0’ 0’’ X B3 100o 30’ 29’’ 259o 29’ 44’’ -21o 00’ 85’’ -10o 50’ 43’’ 89o 79’ 86’’ -4o 99’ 64’’          B3 X 79o 20’ 16’’ 280o 39’ 42’’ +21o 19’ 26’’ +10o 59’ 72’’ 89o 79’ 88’’ 0o 00’ 00’’ B3 Y 81o 26’ 46’’ 278o 32’ 59’’ +7o 06’ 13’’ +3o 03’ 07’’ 84o 29’ 53’’ 185o 50’ 35’’         Y B3 90o 0’ 0’’ 270o 0’ 0’’ 0’’ 0’’ 90o 0’ 0’’ 0o 0’ 0’’ Y A3 90o 0’ 0’’ 90o 0’ 0’’ 0’’ 0’’ 90o 0’ 0’’ 90o 00’ 00’’ Angular misclose Calculate your angular misclose Allowable Misclose = 30”+ 5 where k (for a Total Station) is 5” and n is the number of angles. = 50’’ Remove angular misclose Obs Angle corr Final Angle AYB 67o 25’ 83’’ +5 67o 25’ 88’’ AXB 120o 50’ 92’’ +5 120o 50’ 97’’ XAY 83o 70’ 42’’ +5 83o 70’ 47’’ XBY 88o 52’ 63’’ +5 88o 52’ 68’’ Use the adjusted angles to calculate bearings Calculate East and North Stn 0 ` “ Dist E = Sin (Bearing) x distance ∆N =Cos (Bearing)*distance Stn 0 ` “ Dist E = Sin (Bearing) x distance ∆N =Cos (Bearing)*distance A 292 74 17 45.382 -45.087 -5.163 Y 28 75 62 52.36 -47.109 +22.855 B 24 36 15 65.56 +24.48 -6.818 X 78 69 19 48.82 +46.111 -16.037 Linear misclose2 =+ Linear misclose =-0.0321 Calculate The Coordinates This Example Assumes A:(4500.000,7200.000) East Coordinate Of B = East Coordinate of A+E +Corr E East Coordinate Of B = 5000.000+(-181.303)+(-0.002) Stn 0 ` “ Dist E = Sin (Bearing) x distance ∆N =Cos (Bearing)*distance East North A 4500 7200 292 74 17 45.382 -45.087 -5.163 Y 4,454.913 7,194.837 28 75 62 52.36 -47.109 +22.855 B 4,407.804 7,222.855 24 36 15 65.56 +24.48 -6.818 X 4,432.284 7,216.037 78 69 19 48.82 +46.111 -16.037 A 4500 7200 Summary After completing the project, I have managed to connect theory and practical in the field of survey engineering. This field experience has given me insides which will help me succeed in future by trying to enhance and reduce the weaknesses discovered during the study. One of strengths that come out clearly is the essence of teamwork, communication, humility and focus. Communication was critical in producing reports after the fieldwork has been done. While teamwork and humility ensured that I accepted comments made by team members. During the experiment, I realised that I was unable to use a tripod, a spirit level measure and horizontal lines. Most of the levelling equipments gave me difficulties in obtaining accurate results although I followed all the procedures that were necessary for the project. Although there was a desire to have accurate results in future, that kind of weakness will lead to my failure in future. This area will need to be improved by going out for another experiment. I also realised that I had a weakness in interacting with my team mates especially in giving feedback. Therefore I need to increase my level of interaction with class members. The two peg test for levelling did not give me much difficult because I did it successively. Read More