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The paper "The Melting Point of Pure Tin" suggests that this experiment was conducted to identify the melting point of pure Tin. To find that, a ceramic crucible that contained Tin was heated in the furnace for up to 400C. 400C is considerably above the estimated melting point of pure Tin…
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Tin Melting Experiment 3-8-11 Group 6 Summary This experiment was conducted to identify the melting point of pure Tin. In order to find that, a ceramic crucible that contained Tin was heated in the furnace up to 400C. 400C is considerably above the estimated melting point of pure Tin. To keep the sample from getting oxidized, nitrogen was introduced into the furnace while it was made sure, that no oxygen entered it. Tin’s melting point was virtually determined through its transition from solid to molten state. Tin was then shifted into a coffee can. Sand was already there in the can. A thermocouple sheath made of stainless steel was also introduced into it exactly quarter of an inch above the crucible’s base. The isolation was created with a glass fiber that decelerated the cooling process. The experiment used this time to note the data. He noticed the alteration of temperature with respect to time. Until the temperature of Tin reached 150C, temperature was noted several times at an interval of 5 seconds. 150C is essentially 10C above the freezing point of Tin. This was done so as to ensure that the thermocouple sheath does not get frozen. Once the data was completely collected, the Tin cooling curve was developed using the information of temperature versus time.
Abstract
This experiment was intended to find out Tin’s melting point for which, a ceramic crucible that contained Tin was heated in a furnace enough to get the temperature above Tin’s estimated melting point. The molten Tin was shifted to the coffee can filled with sand. A thermocouple sheath was placed into the molten Tin and was isolated with a glass fiber. The cooling process was slowed down due to that and the experimenter noted the data meanwhile. Finally, with the help of data of temperature alteration with time, the Tin cooling curve was formulated. The collected data was compared with the real data noted in the periodic table to identify the extent of errors that may possibly have occurred during the experiment.
Table of contents
Summary…………………………………………………… page 2
Abstract…………………………………………………….. page 3
Table of contents…………………………………………… page 4
Introduction………………………………………………… page 5
Experimental procedure……………………………………. page 6-7
Results ……………………………………………………... page 8-10
Discussion………………………………………………….. page 11
Conclusion…………………………………………………. page 12
Introduction
Different elements exhibit different behaviors with respect to freezing and melting processes. There are elements that have a well defined freezing and melting point, while there are others that do not have a specific melting and freezing point. This experiment was conducted to determine the melting point of pure Tin from the Tin cooling curve.
Experimental procedure
A. Equipment used
1. Furnace.
2. Omege temperature meter.
3. Glass fiber for insulation.
4. Thermocouple sheath.
5. Plastic gloves.
6. Coffee can containing sand.
7. Ceramic crucible.
B. Procedure
1. A ceramic crucible that contained Tin was heated in the furnace up to 400C. 400C is considerably above the estimated melting point of pure Tin.
2. To keep the sample from getting oxidized, nitrogen was introduced into the furnace while it was made sure, that no oxygen entered it.
3. Tin’s melting point was virtually determined through its transition from solid to molten state.
4. Tin was then shifted into a coffee can. Sand was already there in the can. A thermocouple sheath made of stainless steel was also introduced into it exactly quarter of an inch above the crucible’s base. The isolation was created with a glass fiber that decelerated the cooling process.
5. The experiment used this time to note the data. He noticed the alteration of temperature with respect to time. Until the temperature of Tin reached 150C, temperature was noted several times at an interval of 5 seconds. 150C is essentially 10C above the freezing point of Tin. This was done so as to ensure that the thermocouple sheath does not get frozen.
6. Once the data was completely collected, the Tin cooling curve was developed using the information of temperature versus time.
Results
A. Table of data
Time
Temp
Time
Temp
Time
Temp
Time
Temp
0
450
110
313.9
225
251
340
212.7
5
427
115
309
230
249.2
345
229.3
10
420
120
306
235
247.9
350
232.8
15
411
125
303
240
245
355
232.9
20
405
130
300.1
245
243.3
360
232.9
25
398
135
296
250
241.3
365
233
30
391
140
293.2
255
239.4
370
233
35
384.1
145
290.4
260
237.4
375
233
40
378.4
150
287.3
265
236
380
233
45
371.1
155
285
270
234.3
385
233
50
367
160
282
275
232.5
390
233.1
55
361.2
165
279.2
280
230
395
233
60
356.6
170
276.6
285
229.1
400
233
65
351.4
175
273.8
290
227.4
405
233.1
70
346
180
271.5
295
226.4
410
233
75
341
185
268.5
300
224.4
415
233
80
337
190
266.6
305
223
420
233
85
333
195
264.1
310
221.4
425
233
90
328
200
261.8
315
220
430
233
95
324.5
205
259.2
320
218.5
435
233
100
320.3
210
257.6
325
216.9
440
233
105
317
215
255.3
330
215.4
445
233
220
253.3
335
214.1
450
233
Time
Temp
Time
Temp
Time
Temp
Time
Temp
455
233
575
227.1
690
188
805
164.9
460
233
580
224.6
695
186.9
810
163.8
465
233
585
222.1
700
185
815
163
470
233
590
220
705
184.5
820
162.3
475
233
595
217.6
710
183.3
825
161.6
480
233
600
215.5
715
182.2
830
160.7
485
233
605
214.9
720
181.1
835
160
490
233
610
212
725
180
840
159.3
495
233
615
210
730
179
845
158.4
500
232.9
620
208
735
177
850
157.7
505
232.9
625
206
740
176.8
855
156.7
510
232.9
630
205
745
175.7
860
156
515
232.8
635
203.8
750
174.8
865
155.4
520
232.8
640
201.9
755
173.7
870
154.6
525
232.7
645
200
760
173
875
153.9
530
232.7
650
199
765
171.8
880
153.4
535
232.6
655
197.2
770
170.9
885
152.7
540
232.3
660
196
775
170
890
152.1
545
232
665
194.5
780
169
895
151.3
550
231.7
670
193.2
785
168.2
900
150.7
555
231.3
675
192
790
167.3
905
150
560
230.8
680
190.8
795
166.6
910
149.3
565
230.2
685
189
800
165.5
915
148.8
570
229.2
B. The cooling curve
Table 1
C. Class results
Tuesday:(232+233+233)
Wednesday:(233+233+233+233+233)
Ave=233
Percent error= ((calculated-actual)/actual)*100=.0370
Discussion
The collected data was compared with the real data noted in the periodic table to identify the extent of errors that may possibly have occurred during the experiment. The following factors are potential causes of error in the experiment:
1. Calibration of temperature meter
2. Calibration of thermo couple
3. Amount of decimal places in the temperature meter.
Conclusion
The minute error found is quite normal given the insufficient calibration of equipment used. In addition to that, some error might also have been introduced because of insulation. Overall, however, the collected results do not match with the real results. Therefore, the experiment can not be termed as perfect and free of error.
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