Water of Hydration in the Reagent - Lab Report Example

The results enumerate the fact that there was a need to repeat the experiment times in 3 different cycles s as to be sure about the results. The mass of the hydrated salt is the mass of the crucible lid and hydrated salt, less the mass of the crucible and lid alone; 22.

678 – 22.042 = 0.636. For the second cycle, the mass of the water alone is the mass of the crucible lid and hydrate, less the mass of the crucible lid and residue after heating. That gives 22.678 – 22.455 = 0.223. Because the second cycle represents a time when more accuracy is sought as opposed to the first cycle, the mass from the second cycle is taken for use in the establishment of the % of the water of hydration. The % of the water of hydration is equal to the mass of the water of hydration alone, divided by the mass of the hydrated salt and the result is multiplied by 100%.

That gives, (0.223 / 0.636 ) * 100 = 4% to the nearest whole number. The experiment, however, proved that indeed there is the water of hydration in the reagent and that has weight which is shaded off by heating the reagent