What Speed Increase Do Aerofoils Give to an F1 Car - Assignment Example

WHAT SPEED INCREASE DO AEROFOILS GIVE TO AN F1 CAR? INRODUCTION Airfoils make cars faster at the bends and it is controlled by the wing setting. Larger wings setting slow the due to large down force. The skill is as a result of balancing the areas of pressure and the car maintains balance as it moves and also eliminates the drag while the car slips easily in the air. In this report we are going to compare movement of F1 car with and without airfoil. The forces involved are centripetal force, frictional force and normal force. Normal force, FN is the product of mass and it’s acceleration due to gravity ; FN = Mg Frictional force, Ff = µ FN where µ is the coefficient of friction. Centripetal force Fc, is the force around a circular bend Discussion Results Without airfoil FN = M g = (M) (9.8 m/s2)= 620×9.81= 6082.2N For flat curve, the centripetal force is supplied by the friction force, Ff, Ff = µ FN F f = µ M 9.8 m/s 2 Ff = Fnet = Fc Fc = M v2 / r i) Using Intermediate tyres in the dry: µ=0.7 Ff = µ FN Ff = 0.7×6082.2 = 4257.54N a) Centripetal force, Fc, at radius 50m Fc = 620× = 4257.54 = 620× V = = 18.53m/s speed Ff Fc m/s N N 0 4257.54 0.00 1 4257.54 12.40 2 4257.54 49.60 3 4257.54 111.60 4 4257.54 198.40 5 4257.54 310.00 6 4257.54 446.40 7 4257.54 607.60 8 4257.54 793.60 9 4257.54 1004.40 10 4257.54 1240.00 11 4257.54 1500.40 12 4257.54 1785.60 13 4257.54 2095.60 14 4257.54 2430.40 15 4257.54 2790.00 16 4257.54 3174.40 17 4257.54 3583.60 18 4257.54 4017.60 19 4257.54 4476.40 20 4257.54 4960.00 21 4257.54 5468.40 22 4257.54 6001.60 23 4257.54 6559.60 24 4257.54 7142.40 25 4257.54 7750.00 26 4257.54 8382.40 27 4257.54 9039.60 28 4257.54 9721.60 29 4257.54 10428.40 30 4257.54 11160.00 b) At radius 100m V = = 26.2m/s c) At radius 200m V = = 37.06m/s d) At radius 500m V = = 58.6m/s ii) Using Intermediate tyres in the wet: µ=0.4 Ff = 0.4×6082.2 = 2432.88N a) Centripetal force, Fc, at radius 50m Fc = 620× = 2432.88 = 620× V = = 14m/s speed Ff Fc m/s N N 0 2432.88 0.00 1 2432.88 12.40 2 2432.88 49.60 3 2432.88 111.60 4 2432.88 198.40 5 2432.88 310.00 6 2432.88 446.40 7 2432.88 607.60 8 2432.88 793.60 9 2432.88 1004.40 10 2432.88 1240.00 11 2432.88 1500.40 12 2432.88 1785.60 13 2432.88 2095.60 14 2432.88 2430.40 15 2432.88 2790.00 16 2432.88 3174.40 17 2432.88 3583.60 18 2432.88 4017.60 19 2432.88 4476.40 20 2432.88 4960.00 21 2432.88 5468.40 22 2432.88 6001.60 23 2432.88 6559.60 24 2432.88 7142.40 25 2432.88 7750.00 26 2432.88 8382.40 27 2432.88 9039.60 28 2432.88 9721.60 29 2432.88 10428.40 30 2432.88 11160.00 b) At radius 100m V = = 19.81m/s c) At radius 200m V = = 28.01m/s d) At radius 500m V = = 44.29m/s iii) Using Slicks in the dry: µ=0.9 Ff = 0.9×6082.2 = 5473.98N a) Centripetal force, Fc, at radius 50m Fc = 620× = 5473.98 = 620× V = = 21.01m/s speed Ff Fc m/s N N 0 5473.98 0.00 1 5473.98 12.40 2 5473.98 49.60 3 5473.98 111.60 4 5473.98 198.40 5 5473.98 310.00 6 5473.98 446.40 7 5473.98 607.60 8 5473.98 793.60 9 5473.98 1004.40 10 5473.98 1240.00 11 5473.98 1500.40 12 5473.98 1785.60 13 5473.98 2095.60 14 5473.98 2430.40 15 5473.98 2790.00 16 5473.98 3174.40 17 5473.98 3583.60 18 5473.98 4017.60 19 5473.98 4476.40 20 5473.98 4960.00 21 5473.98 5468.40 22 5473.98 6001.60 23 5473.98 6559.60 24 5473.98 7142.40 25 5473.98 7750.00 26 5473.98 8382.40 27 5473.98 9039.60 28 5473.98 9721.60 29 5473.98 10428.40 30 5473.98 11160.00 b) At radius 100m V = = 29.71m/s c) At radius 200m V = = 42.02m/s d) At radius 500m V = = 66.44m/s iv) Using Slicks in the wet: µ=0.1 Ff = 0.1×6082.2 = 608.22 N a) Centripetal force, Fc, at radius 50m Fc = 620× = 608.22 = 620× V = = 7m/s speed Ff Fc m/s N N 0 608.22 0.00 1 608.22 12.40 2 608.22 49.60 3 608.22 111.60 Force Vs Velocity graph 4 608.22 198.40 5 608.22 310.00 6 608.22 446.40 7 608.22 607.60 8 608.22 793.60 9 608.22 1004.40 10 608.22 1240.00 11 608.22 1500.40 12 608.22 1785.60 13 608.22 2095.60 14 608.22 2430.40 15 608.22 2790.00 16 608.22 3174.40 17 608.22 3583.60 18 608.22 4017.60 19 608.22 4476.40 20 608.22 4960.00 21 608.22 5468.40 22 608.22 6001.60 23 608.22 6559.60 24 608.22 7142.40 25 608.22 7750.00 26 608.22 8382.40 27 608.22 9039.60 28 608.22 9721.60 29 608.22 10428.40 30 608.22 11160.00 The vehicle slip after 7m/s with the tyre of 0.1 coefficient and radius 50m b) At radius 100m V = = 9.9m/s c) At radius 200m V = = 14m/s d) At radius 500m V = = 22.14m/s 2. From the google maps Width is 1.8m Length 4.05m Span 1.89m Chord 0.45m Results with airfoil X/c Y/c P V 1 -0.522 0.022 103.078 82 2 -0.515 0.045 101.137 218 3 -0.495 0.066 99.529 286 4 -0.463 0.084 98.873 309 5 -0.42 0.098 98.757 313 6 -0.367 0.107 98.898 308 7 -0.304 0.11 99.163 299 8 -0.232 0.108 99.488 287 9 -0.154 0.101 99.835 274 10 -0.071 0.089 100.183 260 11 0.015 0.073 100.514 246 12 0.103 0.054 100.82 233 13 0.19 0.035 101.091 220 14 0.272 0.017 101.323 209 15 0.346 0.001 101.515 199 16 0.41 -0.01 101.666 191 17 0.458 -0.017 101.775 185 18 0.489 -0.021 101.845 181 19 0.499 -0.021 103.396 0 19 0.499 -0.021 103.396 0 18 0.489 -0.021 101.868 179 17 0.458 -0.022 101.825 182 16 0.409 -0.025 101.745 186 15 0.345 -0.031 101.632 193 14 0.269 -0.04 101.487 201 13 0.186 -0.051 101.314 209 12 0.098 -0.063 101.119 219 11 0.009 -0.074 100.91 229 10 -0.078 -0.082 100.702 238 9 -0.163 -0.087 100.51 247 8 -0.241 -0.088 100.357 253 7 -0.312 -0.083 100.277 256 6 -0.375 -0.074 100.316 255 5 -0.427 -0.061 100.543 245 4 -0.469 -0.043 101.065 222 3 -0.499 -0.022 102.002 171 2 -0.517 0 103.149 72 1 -0.522 0.022 103.078 82 Joukowski Airfoil Camber = 0.0 % chord , Thickness = 16.276 % chord , Chord = 0.451 m , Span = 1.859 m , Surface Area = 0.838 sq m , Angle of attack = 2.519 degrees , Standard Earth Atmosphere Altitude = 0 m , Density = 1.224kg/cu m Pressure = 101.261kPa, Temperature = 15C, Airspeed = 211 km/hr , Lift = 547 Newtons Drag = 62 Newtons CONCLUSION From the above results it is true to conclude that the velocity around a bend is increased by reducing the down force of the car. Checking the excel results at the bend it is clear that the speed is 211 km/hr while the lift has been reduced to 547N. Therefore the requirements of the experiment have been met. References F1 pdf provided [Sel081] Read More