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# Exploring Inferential Statistics and Their Discontents - Assignment Example

Summary
Exploring Inferential Statistics and Their Discontents Name Institution Part I Question 1 Jackson (2012) Chapter 8, Pgs. 220-221 (even numbered exercises) 2. a) The test is a one-tailed b) H0: No variation between new and other toothpastes in mean figure of cavities in the entire population…

## Extract of sample"Exploring Inferential Statistics and Their Discontents"

Download file to see previous pages Answer: Critical t: ±2.0687 at DF= 23 Critical t: ±2.1604 at DF= 13 He is more likely to make Type II error. 6. a) The test is two tailed. b) Ho: u = 58 Ha: u is NOT equal to 58 c) Calculate standard deviation and mean for the sample in the beginning then calculate t-value by using the following formula. t = (Xbar - u)* sqrt n/s n stand for the sample size s stand for the sample standard deviation Xbar stand for the sample mean u = 58 d) t-critical value “Degrees of freedom” = n - 1 = 14 - 1 = 13 level of significance = alpha = 5% = 0.05 t-critical value = 2.145 e) Ho will be rejected if the computed t value is greater than the critical value f) 95% confidence interval for u can be achieved by applying the subsequent formula. Sample mean +/- t critical value*s/sqrt n 8. a. X^2 obtained = 4.74 b. df of the test = 1 c. x^2 critical value = 3.84 d. This question can be done assuming it is on assessment of a hypothesis and using z test. Jackson (2012) Chapter 8, Pgs. 273-275 (even numbered exercises) 2. a. Statistical test: a two-proportion t-interval b. Ho: students listening to music while studying have the similar scores as students not listening to music Ha: students listening to music while studying have the worse scores than students not listening to music c. with Music Without Music Mean 6 7.75 Variance 1.142857143 2.214285714 Observations 8 8 Pearson Correlation equals -0.449013255 Hypothesized Mean Difference is Zero Degree of Freedom = 7 t Stat = -2.262609773 P(T ...Download file to see next pagesRead More
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