## CHECK THESE SAMPLES OF N2

...Absorption of Infrared photons by Greenhouse Gases (GHGs) Background information Greenhouse Gases (GHGs) are liable for the earth’s augmented temperature, which emanates from their diverse atomic characteristics. Each gas has individual rate and intensity through which it contributes to the greenhouse effect where it predominantly lies in its structural orientation. This lies in the number and atoms’ type, which constitute their individual molecules. For instance, diatomic molecules like **N2** & O2 have similar atoms contradictory H2O, CH4, and CO2 whose atoms plus bonds differ radically. This influences their rate of IR absorption. Molecules absorb and emit energy principally emanating from:- 1. Electron excitation...

3 Pages(750 words)Lab Report

...how a bomb is smuggled on board a plane containing Hitler in order to kill him. This sets up the story of who is involved in the eventual plot that is the highlight of the film. It frames the desperation of those involved as well as the difficulty for killing Hitler despite the numerous attempts. There are three key narratives that frame the story. The first (N1) is that of Major General Henning von Treskow played by Kenneth Branagh who is the first in the film to attempt to assassinate Hitler. The second (**N2**) is that of Colonel Claus von Stauffenberg, played by Tom Cruise, whose personal life and his decision making is used to show how the event of the attempted coup affected the private life of a key participant....

10 Pages(2500 words)Essay

...Civil Engineering Numerical Analysis The governing equation for the given problem is ; ; The solution to the above equations can be determined using the Galerkin Method. According to Galerkin method the solution of for the above equation is obtained using a test function v.
with u =0 and v=0 at x =0 and integrating by parts following equations are obtained
(1)
Thus this indicates that for u(x) as the solution for displacement in the bar the left hand side of this equation. The linear interpolation functions chosen 3 node bar elements given as shown below
1 2 3
The unknown U is defined across the problem domain using the interpolation functions N1, **N2** and N3 as U= N1U1 + **N2** U2 + N3 U3.
The interpolation... ...

2 Pages(500 words)Assignment

...is consistent with the policy.
3.
Given:
Victorian: Federal:
Sample size (n1): 1600 Sample size (**n2**): 2000
Proportion: 642 Proportion: 861
p1 = 642/1600 = 0.40 p2 = 861/2000 = 0.43
a. The confidence interval for the sample proportions are determined as:
+/- 1.96 (((p1 (1-p1)/n1) + (p2- (1-p2)/**n2**))1/2
(-0.03)+/- 196 (0.00015 + 0.00012) 1/2
The confidence interval lies from -0.062 to 0.002.
b. In order to see if there is a significant difference in the proportion of the populations tested, we till employ a t-test, where:
Ho = p1- p2 = 0
Ha = p1- p2 ≠ 0
We will employ a z-test, where z = p1- p2 / (((p1 (1-p1)/n1) + (p2- (1-p2)/**n2**))1/2. Plugging in the appropriate...

7 Pages(1750 words)Essay

...)
>> subplot(2,1,2),plot(t,q),xlabel(time)
Comparison:
The signal is compared both in frequency and time domain, before and after filtering. As seen in the graphs the amplitude of the signal after filtering is 1. The amplitude thus decreases from 2 to 1, showing 3dB attenuation. In frequency domain the higher frequency coefficients are zero. They cover almost half the total bandwidth. Thus the half band filter has made half of the coefficients zero with 3dB attenuation.
Functions:
function[y,n] = sigadd(x1,n1,x2,**n2**)
n= min(min(n1),min(**n2**)):0.001:max(max(n1),max(**n2**));
y1=zeros(1,length(n));
y2=y1;
y1(find((n>=min(n1))&(n<=max(n1))==1))=x1;
y2(find((n>=min(**n2**))&(n<=max(**n2**))==1))=x2;
y=y1+y2... ;
--------------------
function [y,n] =...

15 Pages(3750 words)Essay

...Objective: "You used the wrong numbers. You should use the following numbers: x1 = 990, n1 = 7356, x2 = 999, **n2** = 7356." Above is the Revision comments for the below order
You can use StatCrunch or the TI to help with this test. Needed information for both tools include:
x1 = number of red
n1 = total number of candies
x2 = number of brown
**n2** = total number of candies
For the TI, you will want 2-PropZTest. Then select the appropriate alternative (not equal), and Calculate then enter. The output will have the test statistic (z), p-value (p), sample p values, weighted p (), then repeat of sample sizes."You used the wrong numbers. You should use the following numbers:
x1 = 990, n1 = 7356, x2 = 999,...

2 Pages(500 words)Speech or Presentation

...Diderot Questions Word Count: 257 page **N2**’s judgment seems to show disappointment. What are the indications of this? What would **N2** have preferred in order to satisfy his expectations of a good story? And how does N1 disagree, or at least defend himself?
The indications that **N2** feels disappointment are demonstrated in his manner of speech. **N2** would have preferred that a good story would make sense. N1 defends himself by rationalizing that it is a good story.
2. In a similar way, N1 accuses **N2** of having listened despite his objections. In this riposte, he sets forth a definition of the good listener much the same way **N2** had attempted to define the good story-teller. Write down these two definitions, structuring your formulation... in a...

1 Pages(250 words)Assignment

...Standard deviation=0.28808
Standard deviation=0.553894
c) Interpretation of the descriptive statistics.
The mean CAL in controls is higher than the mean CAL in the cases. The standard deviations are large implying that the values are highly distributed in the population and are far from the means.
d) The mean CAL values are normally distributed in the two groups. Most of the data points are close to the mean, where as few data points are far from the mean. Therefore, there is a high likelihood that the data follows a normal distribution.
e) The difference in the mean CAL between case and control groups with the corresponding 95% confidence interval.
The confidence interval is given by the formula M1-M2 ± t α/2, df × √(S1/n1+...

4 Pages(1000 words)Essay

...Statistics 18. Marathon Finishers. In a recent New York marathon, 25,221 men finished and 253 dropped out. Also 12,883 women finished and 163 dropped out (bases on data from the New York Times). We want to use a 0.01 significance level to test the claim that the rate of those who finish is the same for men and women.
Claim: the rate of those who finish is the same for men and women.
n1 =25,474 (men)
**n2**=13,046 (women)
X1= 25,221
X2= 12,883
a. Test the claim using a hypothesis test
H0: p0=p1 the rate of those who finish is the same for men and women
H1:p0≠p1 the rate of those who finish is not the same for men and women
Significance level (α) = 0.01
p (bar) = x1+x2 / n1+**n2**
=25,221+12,883 /...

4 Pages(1000 words)Speech or Presentation

...The Scheme’s Properties
Given two nodes, n1, **n2**, with level1, level2 as their levels (the level refers to the level of the element node in the XML tree), and with labels A and B, where global labels are a1.a2…am , ith and b1.b2…bn, , jth respectively and their local labels are La1. La2 and Lb1. Lb2, the label properties can be defined as in the following:
Node Level:
The level information of each node can be derived from its global label as follows:
The level is the number of components in the first part of the node’s global label plus 1 if the second part of the global label exists; i.e. if the SG equals null, the level is the number of component in FG.
e.g. As shown in Fig. 4.1 and Table 4.1, the level of node ‘B’...

12 Pages(3000 words)Essay