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Factors that affect the electric strength of insulating materials
How to determine the electric field strength in high-voltage structures
This is given as E=F/qtest
E represents electric strength, F represents force and quest represents the amount of test charge. From this formula, the ratio of force to the amount of test charge gives the field strength. It is given in Newtons per Coloumb (N/C). This gives the force available per coulomb of charge used as a test charge (Harris 1966).
Advantage
The formula is not complicated and gives the value of the electric field
Disadvantage
The direction of the field is not specified by the field intensity formula. This is because the direction of the force depends on the direction of force detected by a positive charge.
In any direction, the negative rate of change of potential is the component of the electric field of that direction. The differential voltage change is equal to the electric field component in that particular direction times the distance.
dV=-E.eds=-esds
Therefore the electric field is expressed as Es=dv/ds along ds or Es=-∂V/∂s
-Electric strength is related to the intensity of charges on the source but inversely related to the distance from the source.
-The direction in which a positive charge is pushed is the direction of the electric field. This is represented by a vector arrow.
-The number of arrows shows the amount of charge whereas the length of the arrows represents the magnitude of the electric field. Arrow lengths are longer near the charge source than when away.
Advantages
- Easy way of determining if a current is strong or weak by simply looking at the length of lines
-Gives a quick view of the amount of charge on a material
Disadvantages
-Simply tells if a current is weak or strong but not the exact magnitude
-The lines must be limited along an electric line pattern to ensure the readability of the patterns
-It is cumbersome to draw electric lines in highly charged materials
-Readability is reduced where more fields meet
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