Real World Quadratic Functions - Speech or Presentation Example

Real World Quadratic Functions of Real World Quadratic Functions Solution The profit p is given by the equation given below;Where x = number of clerksAnd p = profitWhich is a parabolic equation, vertex in a parabola is defined as the highest point if a parabola opens downward and the lowest point when it opens upward. The value of y should be maximum if the parabola opens downward whereas the value of is minimum if the parabola opens upward profit (Carson, Gillespie, & Jordan, 2010). In this given cast the parabola open downward as the coefficient of the x is negative.

Here instead of y we use p which is the. As the maximum profit occurs at highest value of p which can be found by finding the vertex of the parabola, so the coordinate of x is given by; The standard equation is given as;Now from given equation we get;Using the above values we can find the x coordinate at which profit is maximum;Therefore the number of clerks required for getting maximum profit is 6. Hence manager employs only 6 clerks for attaining the maximum profit.Now buy using the value of x we can get the value of maximum profit.

For this purpose we put the value of x in the equation of profit that is given in the question; As x = 6, so Therefore the maximum profit that is attained by using 6 clerks is 900.The graph for this equation id given below;The above graph show profit as a function of number of clerks that manager employs. The graph shows that the profit follows a parabolic path and changes with the number of the clerks.Application of Parabolic EquationIn different applications every individual is interested in searching for the maximum and minimum value.

The maximum value of the variable that is dependent should be the 2nd coordinate of the vertex in the graph which shows a parabola that opens downward, whereas the minimum value of the variable that is dependent should the 2nd coordinate of the vertex in a graph which shows a parabola that opens upward (Carson, Gillespie, & Jordan, 2010).This is important for the manager because it provides information to him/her about the maximum or minimum profit. In the given case the graph shows the manger that how many of the clerks are required to attain the maximum profit.

This graph also helps the manager in creating a relationship between the number of clerks and the profit earned and from that relation he or she can determine the ideal situation that is required for getting maximum profit, Whereas in case if the manager cannot attain the ideal situation he or she can use the graph and can use it to find out the maximum number that he or she can attain. If ideal conditions are not met then the manager cannot achieve the maximum profit.ReferencesCarson, T., Gillespie, E.

& Jordan, B.E., (2010). Elementary and Intermediate Algebra The Carson Algebra Series. Addison Wesley.