How to Calculate the Broadcast Address - Assignment Example

How to Calculate the Broadcast Address?As any particular subnet mask has not been provided, therefore, the IP address can be considered as a Classful IP address. It means that the IP address is broken down into Classes of Internet Protocol Network. The given IP address 12.2.201.2 (IPA.IPB.IPC.IPD) belongs to Class A range; therefore, 255.0.0.0 (SBA.SBB.SBC.SBD) is a default subnet mask. In this regard, we can say that the network address of the given IP address should be 12.0.0.0 (Answer). As network address is equal to IPA & SBA.IPB & SBB.IPC & SBC.

IPD & SBD (PlexusWorld, 2009).For configuration, you need to go to the control panel then click the icon of the network and sharing center, on the left side of the opened window please click change adapter settings. Now you have to right click on the adapter and go to properties option. The Networking tab would be opened, not please select Internet Protocol version 4, press properties button. Please enter the IP address in the respective textbox 12.2.201.2, due to class ‘A’ network the subnet mask would automatically be filled as 255.0.0.0.Ans.

of Q # 2The given IP address 211.106.32.0 falls into the class C range and the subnet mask of the Class C range is 255.255.255.0. We need to subclass the subnet mask 255.255.255.224, its equivalent bitmask in binary is 11111111.11111111.11111111.11100000 (FF.FF.FF.E0). The next network address can be calculated as the first three parts 11111111.11111111.11111111 does not change; therefore the network address would be 211.106.32.32. Moreover, the broadcast address would be 211.106.32.63 (Answer), as the last IP in the subnet is ‘00111111’ equivalent to 63.

It is calculated as the broadcast address = IP address | (! Subnet). In other words, you need the IP address or (operator) the inverted subnet (Pean, 2002).Ans. of Q # 3The given IP address 131.34.0.0 belongs to class B (range of class B is 128.1.0.1 to 191.255.255.254 total 65,000 hosts on each of 16,000 networks). Keeping in view the given IP address, the range of the given host IPs is from 131.34.0.1 to 131.34.15.254, this becomes total 4096 IP addresses that also include network and broadcast addresses.

The three ranges can include from 131.34.16.0 to 131.34.31.255, the second range can be from 131.34.32.0 to 131.34.47.255, the third and the final range can be from 131.34.240.0 to 131.34.255.255.Ans. of Q # 4 The bitmask of the given subnet mask 255.255.255.192 is FF.FF.FF.C0 (192 = C0, where C=1100, and 0=0000) and the IP address 152.19.0.0 belongs to Class B. According to the given subnet mask the range of valid subnet numbers is counting from 0 (0.0 – number 0) to 1023 (255.255 to number 1023) and the total subnets are 1024.

Moreover, as per the given subnet mask the first subnet number should be 152.19.0.0, whereas, the last subnet number should be 152.19.255.192 (Jason, 2003). Ans. of Q # 5The given network ID130.16.0.0 falls into class B, therefore, it should have a subnet mask equivalent to 255.255.0.0. A total number of 256 subnets can be allocated to subnet mask 255.255.255.0 that range from 0 to 255. It’s better to check the next lower number of subnets, the next lower subnet mask is 255.255.254.0 that provides a total number of 128 subnets, and the number is lower than the desired number of subnets 160.

Therefore, the subnet mask 255.255.255.0 would be more appropriate to allocate 160 subnets.ReferencesPlexusWorld. (2009). How to calculate Network Address & Broadcast Address? Retrieved from: http://plexusworld.com/2009/10/how-to-calculate-network-address-broadcast-address/Pean, G. (2002). How to calculate the Broadcast Address? Retrieved from: http://www.shunsoft.net/ipcalc/help/chap07.html Jasson, G. (2003). Quick Subnetting How-To. Retrieved from: http://www.pantz.org/software/tcpip/subnetchart.html