Free

Virtual Lab #3 - Assignment Example

Comments (0) Cite this document
Summary
The two species of Paramecium will survive and increase in number when grown alone in the separate environments and attain the carrying capacity in both cases. However, when the two species are grown together the number of one species of Paramecium will diminish and become…
Download full paperFile format: .doc, available for editing
GRAB THE BEST PAPER96.6% of users find it useful
Virtual Lab #3
Read TextPreview

Extract of sample "Virtual Lab #3"

BIO 113 Virtual Lab #3 Population Biology Table I: Day P. caudatum alone, cells/mL P. aurelia alone, cells/mL P. caudatum mixed, cells/mL P. aurelia mixed, cells/mL
0
2
2
2
2
2
12
8
14
10
4
28
52
22
34
6
48
86
22
68
8
60
96
18
82
10
56
96
10
92
12
56
98
2
92
14
56
96
0
96
16
60
98
0
94
Journal Questions:
1. Make a hypothesis about how you think the two species of Paramecium will grow alone and how they will grow when they are grown together.
The two species of Paramecium will survive and increase in number when grown alone in the separate environments and attain the carrying capacity in both cases. However, when the two species are grown together the number of one species of Paramecium will diminish and become extinct as the other specie attains a constant number after reaching a level that the available resource can support.
2. Explain how you tested your hypothesis.
Three environments were created, the first one with Paramecium caudatum alone, the second with P. aurelia alone and the third with both species to assess their intterraction in the same environment. The two species were grown in the medium separately to determine their growth patterns by counting the number of Paramecium after a given period. The two species were then grown in the same medium to assess the competition for food between themselves and whether the principle of competitive exclusion existed between the species. This was done by counting the number of both Paramecium species in the same environment after the given time interval.
3. On what day did the Paramecium caudatum population reach the carrying capacity of the environment when it was grown alone? How do you know?
On the 8th day Paramecium caudatum attained its maximum capacity of 60 species . The prove for this observation is that the population attained on this day did not increase in the subsequent days (repeated in subsequent days). In fact, the population decreased to 56 cells on 10th day and remained stable until the 16th day when it reached 60 cells again. These observations illustrates that the population attained the maximum that the available food resource can support (carying capacity) because the amount of food available could only support that or fewer number.
4. On what day did the Paramecium aurelia population reach the carrying capacity of the environment? How do you know?
On the 12th day Paramecium aurelia attained the maximum cell population of 98 species.
The population attained on this day was the maximum and did not increase further in the subsequent days of growth (number was repeated), in fact, on the 14th day it decreased to 96 cells and later attained 98 on the 16th day, which illustrates that the population attained the maximum of 98 cells because the amount of food available could only support that number or fewer than that number of cells.
5. Explain the differences in the population growth patterns of the two Paramecium species. What does this tell you about how Paramecium aurelia uses available resources?
The two species exhibited major differences in their growth patterns over the same duration investigated. Growing the species in separate test tubes shows that Paramecium aurelia exhibited almost twice the rate of growth as that of Paramecium caudatum when conditions provided for their growth are the same. This shows that P. aurelia has better capabilities of utilising available resources and overcoming growth limitations like accumulation of toxins than P. caudatum when grown in the same medium or in different environments. Besides, this could mean that one specie P. caudatum uses more food resources as one specie of P. aurelia hence the discrepancy in the number of cells when placed in the environment with similar conditions. The evidence for this observation is seen in the mixed slide. Besides, Therefore, the carrying capacity of P. aurelia is higher than that of P. caudatum
6. Describe what happened when the Paramecium populations were mixed in the same test tube. Do the results support the principle of competitive exclusion?
When the species were in the same test tube, Paramecium aurelia grew at a fater rate than P. caudatum. In fact, P. caudatum grew at the lowest rate than when grown alone. This shows that P. aurelia outcompetes the P. caudatum for the available food as evidenced by its increasing number in the subsequent days while P. caudatum decreases. Besides, another explanation relates to the toxins produced by P. Aurelia, which may play a role in the elimination of P. caudatum. The observation show that P. aurelia has better strategies of utlisation available resources like food, and resistance to accumulated toxins than the P. Caudatum.
The principle of competition exclusion ascribes that under constant ecological factors, two species that competes for similar resource would not coexist. The mixing of the Paramecium species exhibited a perfect competitive exclusion because P. aurelia attained the highest count while P caudatum count became zero (died off). This show that one specie stayed at the highest count while the other died off because it could not compete for the available resource (it lacked resources to survive). In fact, on the 16th day, the numebr of P. caudatum becomes extinct while P. aurelia attains the carrying capacity for thr mixed species, thereby supporting the principle of competitive exclusion.
7. Explain how this experiment demonstrates that no two species can occupy the same niche.
When two species occupies a similar niche, they compete for the same available resources as well as for the biotic and abiotic factors. Given that these species have different genomic composition, one specie is likely to possess superior way of obtaining the available resources more easily than the other. Therefore, natural selection will take its course to drive the other specie to extinction. In fact, if extinction does not take place, the specie must develop capabilities of utilising resources that would not be used by the other specie through niche extension (which did not happen in this experiment). for instance, the experiment proves that mixing of the two species in the same test tube show that P. aurelia outgrows and outcompetes P. caudatum because the number of the latter keeps decreasing and diminishes out as opposed to when cultured alone. Contrary, the number of P. aurelia increased with time and eventually attains the carrying capacity once the number of P. caudatum is zero because it lacked resources. This show that the two species cannot exist in the same niche because the less dominant specie becomes extinct with time as it cannot compete for the available resources.

Post-laboratory Questions:
1. Paramecia possess:
a. A nucleus
b. Flagella
c. A contractile vacuole
d. A and C
e. All of the above
2. The organisms used in this experiment belong to which domain of life?
a. Bacteria
b. Archaea
c. Eukarya
3. What served as the food for the paramecia in this experiment?
a. Rice
b. Oats
c. Bacteria
d. Nothing, they are photosynthetic
4. Which of the following can influence the carrying capacity of a population?
a. Availability of food
b. Availability of water
c. Competition
d. Build up of toxins
e. All of the above
5. Which type of competition would be observed between organisms within the P. caudatum culture?
a. Interspecific
b. Intraspecific
c. There would be no competition, they are of the same species
6. Which culture reached its carrying capacity the fastest in this experiment?
a. P. caudatum, alone
b. P. aurelia, alone
c. P. aurelia, mixed
7. You have counted 30 organisms in your culture on Day 4. The concentration of organisms in this culture is:
a. 15 cells/mL
b. 30 cells/mL
c. 60 cells/mL
d. 90 cells/mL
8. Based upon your data, which culture experienced the greatest rate of exponential growth?
a. P. caudatum, alone
b. P. aurelia, alone
c. P. caudatum, mixed
d. P. aurelia, alone
9. Based upon the data, which organism appeared more efficient at using its resources?
a. P. caudatum
b. P. aurelia
10. In a repeat of this experiment, you found that on Days 10-16 the number of individuals in the P. caudatum, mixed culture began to gradually rise. A possible explanation for this is:
a. There was insufficient food in the culture
b. The temperature warmed enough to allow for more growth
c. A genetic variant of the original population began to experience growth due to its use of a different food (bacterium) source
d. None of the above could lead to this scenario Read More
Cite this document
  • APA
  • MLA
  • CHICAGO
(“Virtual Lab #3 Assignment Example | Topics and Well Written Essays - 250 words”, n.d.)
Virtual Lab #3 Assignment Example | Topics and Well Written Essays - 250 words. Retrieved from https://studentshare.org/biology/1699227-virtual-lab-3
(Virtual Lab #3 Assignment Example | Topics and Well Written Essays - 250 Words)
Virtual Lab #3 Assignment Example | Topics and Well Written Essays - 250 Words. https://studentshare.org/biology/1699227-virtual-lab-3.
“Virtual Lab #3 Assignment Example | Topics and Well Written Essays - 250 Words”, n.d. https://studentshare.org/biology/1699227-virtual-lab-3.
  • Cited: 0 times
Comments (0)
Click to create a comment or rate a document

CHECK THESE SAMPLES OF Virtual Lab #3

Lab report 3

...?Bulk and nanoparticle forms of tea catechins and polyphenols exhibit opposite effects on DNA damaged lymphocytes of colorectal cancer patients Abstract Tea catechin epigallocatechin-3-gallate (EGCG), and other polyphenols such as theaflavins (TF) are increasingly proving useful as chemopreventives in a number of human cancers, but without affecting the normal cells. The polyphenols in tea are known to have antioxidant properties which can quench free radical species, and also pro-oxidant activities that appear to be responsible for the induction of apoptosis in tumor cells. The bioavailability of these natural compounds is an important factor that determines their efficacy. Studies have shown a generally low...
12 Pages(3000 words)Lab Report

Lab #3

... OF WINDSOR 02-02-250 BASIC QUANTITATIVE METHODS Assignment #3 Introduction to Hypothesis Testing ID Lab section/instructor Date Exercise Questions 1. For the Number of hours watching television—“tvhours” variable, run the appropriate statistics and visual representation and assess the distribution. ( 2 marks) a) Briefly interpret the results for the “tvhours” variable. Are people watching a lot of TV? The average number of hours per day that respondents (whole population) watch television is about 2.9 hours (SD = 2.24). About half of the respondents watch television up to 2 hours per day. About 50% of the respondents watch television in between 2 to 4 hours per day. Most of the respondents watch television 2 hours per day... . The...
2 Pages(500 words)Speech or Presentation

Temperature and Equilibrium Virtual Lab

...Running Head: Temperature and Equilibrium Virtual Lab PHYSICS University: Course: Tutor: Date: 1. According to NOAA, the hurricane season begins June 1st to 30th November. It is also forecasted that there shall be severe thunderstorms in the coming weeks. 2. Imbalances in nature cannot be prevented but people can prepare for them. According to CDC, when under a hurricane watch, the following can be done in preparation: People should learn about emergency plans, warning signals evacuation routes and locations of emergency shelters. People should identify potential hazards and know how to secure or protect them before the hurricane strikes. Homes should acquire fire extinguishers. Having post...
1 Pages(250 words)Essay

Lab 3

...compartments on the two sides of the cell: inside and outside. There are specific functions for proteins embedded in the interior of the phospholipid bilayer. They carry out various functions such as selective transport of molecules and cell to cell identification. Thus, the main function of the plasma membrane is to control the active and passive movement of various substances into and out of the cell. 3. Describe the differences between animal and plant cells.  The main difference between animal and plant cells is the presence of a cell wall in plant cells which has a rigid, rectangular-shaped structure.  A cell wall is composed of cellulose, hemicellulose, lignin, enzymes and structural proteins. Animal cells do not...
5 Pages(1250 words)Essay

Week 3 Lab

...Week 3: Assignment Week 3: Assignment Level 0: In level 0 the goal is to login into the shell and read the next level (level 1) password from the file readme in the home directory. We Ssh to bandit0@bandit.labs.overthewire.org to enter the shell. 1 2 3 4 5 bandit0@benedict (Linux / Unix Command: bash):~$ ls -lh total 4.0K -rw-r----- 1 bandit1 bandit0 33 Jun  6 13:59 readme bandit0@benedict:~$ cat readme ******************************** Level 1 The goal was to obtain the password from the file named “-“in the home directory and use the password for the next level. Now in the shell it is noticed that the readme file is in our home directory. We “cat” it to obtain the password. The only...
1 Pages(250 words)Assignment

Week 3 lab cis175

...Week 3 lab cis175 Topologies There are several types of topologies which could be applied in such a case. Example of that includes LAN and point to point network. Therefore in this case the best is the LAN. It means Local Area Network (Spurgeon, 2009). The reason for this is that any node in the LAN contains more than one physical link to all other devices in the Network (Hekmat, 2006). a. When such links are mapped graphically they form into a geometrical shape. That shape can be used to describe the topography of the network. For this reason, mapping the flow of the data within the network components would determine the topology of the network logically (Spurgeon, 2009). 2. The best would be peer to peer network. The reasons... 3 lab...
1 Pages(250 words)Assignment

Geomorphology Lab 3

...Introduction The degree of tombstone weathering is figured to rely on various factors given that the some tombstone stayslonger than others do. One of the major the factor that can be measured effectively is the age of the gravestone. Through calibrated relative dating, that involves dating them relative to each other, the age of the tombstones can be arrived at. Other factors that affect weathering degree of a tombstone include type of rock, height, length and thickness. Through exploring these factors, the knowledge about the degree of weathering on tombstones is established. Further, a model for predicting age can be succinctly tested based on weathering degree. As the result of the above concepts, this lab was...
2 Pages(500 words)Lab Report

Network Management: Lab 3

...and external router configs. The hostname and fa00 interface must be set up on both internal and external routers. The configuration process allows a number of activities on the router such as denying access to a specific IP address, adding a password or securing virtual terminal lines. For instance, we can deny access to 12.12.12.15 to prevent it from accessing internal network, the configuration is as follows (Anonymous, 2012): conf t: access list 1-100 deny/permit 12.12.12.15. The number “12.12.12.15” represents the IP address to be blocked in the internal network. In the internal router configuration interface, the following line of code is inputted: Internal (Config) #access-list 1 deny 12.12.12.15. Internal...
1 Pages(250 words)Assignment

Virtual lab #3

...you tested your hypothesis. Three tubes were used to test the hypothesis. The first tube contained Paramecium caudatum while the second one had Paramecium aurelia. The two species were mixed in the third tube. A sample of 0.5ml was put on three slides for observation under the microscope. The three slides were observed severally and the number of species counted and recorded. 3. On what day did the Paramecium caudatum population reach the carrying capacity of the environment when it was grown alone? How do you know? Paramecium caudatum reached the carrying capacity of the environment on the 10th day when grown alone. To support the claim, the species attained its highest count on that day. The species attained a...
1 Pages(250 words)Assignment

Virtual lab 3

...Virtual Lab 3 Table I: Day P. caudatum alone, cells/mL P. aurelia alone, cells/mL P. caudatum mixed, cells/mL P. aurelia mixed, cells/mL 0 1 1 1 1 2 6 5 5 3 4 14 27 11 16 6 24 40 9 31 8 28 48 7 39 10 28 50 5 46 12 28 51 3 48 14 28 48 0 49 16 28 48 0 49 Journal Questions: Question 1 When a paramecium is growing individually, it will thrive considering that it has no competition. This will enable it to grow to its complete size with the readily available resources. On the other hand, when the Paramecium species are grown jointly, one of them will turn out stronger than the other and develop even faster and bigger. As a result, the weak one will begin to...
1 Pages(250 words)Assignment
sponsored ads
We use cookies to create the best experience for you. Keep on browsing if you are OK with that, or find out how to manage cookies.

Let us find you another Assignment on topic Virtual Lab #3 for FREE!

Contact Us