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  • Calculate the atomic radius of iridium., given that Ir has an FFC crystal structure, a density of 22g/cm3 and atomic weight of 192.2 g/mol.
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updated 1 month ago

Calculate the atomic radius of iridium., given that Ir has an FFC crystal structure, a density of 22g/cm3 and atomic weight of 192.2 g/mol.

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1 Answer
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updated 7 months ago

For FCC (face center cubic), n = 4 atoms/unit cell

Vc = 16R3√2  and

ρ = nAIr/VcNA

Combining and solving for R

R = (nAIr/16ρNA√2) = [(4 atoms/unit cell)(192.2 g/mole)/(√2)(16)(22 g/cm3)(6.02x1023 atoms/mole)]1/3 = radius in cm

 

Solution

We are asked to determine the radius of an iridium atom, given that Ir has an FCC crystal structure. For FCC, n=4 atoms/unit cell, and VC=16R32 (Equation 3.4). Now,

=

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