Quantitative data analysis - Assignment Example

we also have 44 people in the 2 (v26) (N) and on average, they have 68 V01 with standard deviation of 28.175 v01.the last column shows the two groups Std error mean. Basing on table 2, the p value of Levenes test is .185.In this case, this p value is greater than 0.05 the alpha. Therefore, we will have to use the middle row of the output (‘labeled Equal variances assumed.’).So we will have to assume that the variances are equal and we need to use the middle row of the output. The labeled column ‘‘t’’, provides a calculated t value.

In this case the t value is -3.961 assuming equal variance (the sign is ignored for two tailed t test). The labeled column df provides the degree of freedom related with the test. In this case we have 106 degrees of freedom. The labeled column sig (2 –tailed) provides p value related to the t test. In this case, the p value 0.185. The sixth step is to decide if we have to reject the null hypothesis. In this case: If p ≤ α , then reject H0.Therefore,0.185 is not equal or less than 0.05.so we fail to reject the null hypothesis.

This means that we failed to observe a difference in the attitude to catalogue shopping between men and women. As shown in table 3, for each dependent variable, the output shows the sample size, minimum, maximum standard deviation, standard error and confidence interval for every independent variable level (quasi) In this case, the p value of 0.520 is greater than the 0.05; we fail to reject the null hypothesis. This means that there is limited evidence that the variances aren’t equal as well as the variance assumption homogeneity may fit.

The 2 is the between groups degrees of freedom, 105 is within groups degrees of freedom,0.723 is the F ratio from the F column,0.487 is the p value and 986.098 is within groups mean square estimate of